Nope, it is not.
It is a strong acid only for the first hydrogen ion that is produced. (1) H2SO4 --> H+ + HSO4^- The remaining bisulfate ion, HSO4^-, is a weak acid and only partially dissociates. (2) HSO4^- <==> H+ + SO4^2- A misconception is that since sulfuric acid is a strong acid, that it dissociates like this: (3) H2SO4 --> 2H+ + SO4^2- That simply isn't the case except for extremely dilute solutions. As the concentration of the acid decreases, the acid behaves more and more like a strong diporotic acid. At "infinite dilution" it is accurate to write the dissociation as equation (3).
It is Ca(OH)2 , which is a strong alkali.
The conjugate acid of SO4^2- is HSO4^-
Zn(NO3)2 is zinc nitrate and it is a strong electrolyte.
Nope, it is not.
It is a strong acid only for the first hydrogen ion that is produced. (1) H2SO4 --> H+ + HSO4^- The remaining bisulfate ion, HSO4^-, is a weak acid and only partially dissociates. (2) HSO4^- <==> H+ + SO4^2- A misconception is that since sulfuric acid is a strong acid, that it dissociates like this: (3) H2SO4 --> 2H+ + SO4^2- That simply isn't the case except for extremely dilute solutions. As the concentration of the acid decreases, the acid behaves more and more like a strong diporotic acid. At "infinite dilution" it is accurate to write the dissociation as equation (3).
1.Strong Sector, Strong competitive positioning 2.Strong Sector, Weak competitive positioning 3.Weak Sector, Strong competitive positioning 4.Weak Sector, Weak competitive positioning
weak weak
SO4 is not a molecule. (SO4)2- is the sulfate ion.
it is weak and strong because it neutralises acids. So its strong not weak but weak not strong.
Sr(OH)2 is considered a strong base
It is Ca(OH)2 , which is a strong alkali.
It is SO4 -2 named as sulphate ion.
Zn(NO3)2 is zinc nitrate and it is a strong electrolyte.
The conjugate acid of SO4^2- is HSO4^-
Fe+3 SO4-2