The bonding in Mo(CN)84- anion as been described in terms of sp3d4 hybridisation. The geometry of the hybrid bonds is "dodecahedral". The use of hybridisation to describe the bonding in transition metal complexes is very old school and other metods are generally used nowadays. There are some horrible pictures of this geometry on the web, try googling books for pictures.
I think XeF6 2+ is an example. Pentagonal bi-pyramidal. 5F on one plane, 1F under the plane and e- pair above. Is it works? XeF6+2 has 6 electrons pairs arround central atom Xe so it should be a regular octahedral structure with Sp3d2 hybridization, XeF6 should be pentagonal bipyramid with Sp3d3 hybridization.
Edit: Actually, it has been experimentally determined that the geometry adopted by XeF6 is a distorted octahedral geometry. It's difficult to explain without using pictures, so I'll leave it to you, to search for "distorted octahedral molecular geometry" on <insert search engine name here> (or rather,
After the sp3 hybridization the electrons will begin to jump to the d orbitals, rather than p orbitals.
No - tungsten (W) always has 74 protons. If any atom has 75 protons, it is rhenium (Re).
If it is possible without any other nuclear reactions to be done, it'll give you an isotope of iridium.
It is not correct: if an atom is divided it is not the original atom.
An atom is larger than a neutron; a neutron is a part of any atom except a hydrogen atom.
Any neutrons that the atom contains.
The central atom of PCl5 is P. In this case, phosphorous has an sp3d hybridization. It is connected to 5 other atoms, one more than the 4 for sp3 hybridization.
1/2[No.of Single Bonds in compound+Valency of the Central atom+Charge of the compound].Example: XeO3Hybridization=1/2[0+8+0]=1/2(8)=4So Hybridization is SP3.Another Example:- XeF6Hybridization=1/2(8+6+0)=1/2(14)=7So Hybridization of XeF6 sp3d3We can try take all examples find the Hybridization that componds.there's one easy method too... Its sigma + lone pairs..............In XeO3, There are 3 sigma bonds and one lone pair... Therefore hybridisation is 4. its sp3.... Similarly its for XeF6....
The atom. Anything smaller is an atomic particle from which all elements are made.
No - tungsten (W) always has 74 protons. If any atom has 75 protons, it is rhenium (Re).
Any electrical charge for the neutral atom. Uranium valences are: 3,4,5,6, 7, possible also 2 in UO.
Your question is a little off, because atoms do not contain different elements; any given atom is an element, for example, a hydrogen atom, an oxygen atom, etc. An atom by definition is the smallest possible amount of a specific element. If you would like to know why atoms are a specific element, that is determined by the number of protons in the nucleus.
The center of an atom of any element is the nucleus.
If you need to ask, you probably can't. Californium is an extremely rare element produced in "atom smashers". If that doesn't suggest some possible sources to you, you don't have any business having any.
For any element an atom contains EQUAL number of protons and electrons. An atom has no charge. If any given atom has an unequal number of electrons and protons it is no longer an atom, but an ION.
Unless becoming smaller than an atom and traveling through the space in between particles.... no
If it is possible without any other nuclear reactions to be done, it'll give you an isotope of iridium.
wo. A strange question! if you hybridise the 3s and 3 p orbitals you end up with sp3 and still get the same answer. Perhaps the hybridisation involves d orbitals, if that is what you are being taught.