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On a three phase system with a line to line voltage of 13800, a wye connection will give you a voltage of, 13800/1.73 = 7977 volts to ground.
Power = voltage times current, and the power loss is the loss in the line, I^2 * R. At 11,000 volts, the current will be (11,000 / 415 = ) 3.77% of what it is at 415 volts. So the power loss in the line at 11,000 volts will be (3.77% ^2 = ) .14% of what it is at 415 volts.
Wouldn't this depend on the voltage of the system? Like if it is a 460 or 208v system it would be 208 or 460v. There should be 3 lines L1 L2 and L3 all measure the input voltage. The wye or star point voltage on a three phase system is the square root of three. This number (1.73) is divided into the three phase voltage to get the voltage to neutral (ground). 208/1.73 = 120 volts, 415/1.73 = 240 volts, 480/1.73 = 277 volts, 600/1.73 = 347 volts.
With the meter on the voltage scale you will read zero volts across the blown fuse. From the bottom terminal of the service switch fuse to ground you will read zero volts and from the top terminal of the service switch fuse to ground you will read 120 volts. The multimeter will read 0
Peak - neutral for 120 volts RMS is 169 volts, or 120 * sqrt(2) Peak to peak will be 2 x this value, or 339 volts.
A voltmeter works by measuring the amount of volts of electricity being given by an electrical line or battery. A digital voltmeter has an easier to read display and is also more accurate.
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On a three phase system with a line to line voltage of 13800, a wye connection will give you a voltage of, 13800/1.73 = 7977 volts to ground.
you make a line graph and then put a scale on it
A line or bar graph is ideal for showing trends.
Power = voltage times current, and the power loss is the loss in the line, I^2 * R. At 11,000 volts, the current will be (11,000 / 415 = ) 3.77% of what it is at 415 volts. So the power loss in the line at 11,000 volts will be (3.77% ^2 = ) .14% of what it is at 415 volts.
48 VOLTS
I checked with my other meter and get 120 volts!