Zn(s) + CuSO4(aq) --> ZnSO4(aq) + Cu(s) The copper will plate out on the zinc. The net ionic reaction is: Zn(s) + Cu+2(aq) --> Zn+2(aq) + Cu(s)
H, Mg, Zn, Cu
potassium
Zn + CuBr2 = Cu + ZnBr2
Zinc and Iodide combine to form zinc iodide. The reaction is a combination reaction and also a redox reaction. A combination reaction is when two elements combine to form a single compound. A redox reaction is when one of the element loses an electron (zinc) and the other one gains electrons (iodide). Hope this helps! ~Kim
This is a redox reaction.
Zn(s) --> Zn2+(aq) + 2e : Oxidation Cu+(aq) + 1e --> Cu(s) : Reduction
The reaction Zn + CuCl2 --> Cu + ZnCl2 is a single-replacement reaction.
Zn + CuSO4 -> ZnSO4 + Cu (molecular equation) Zn (s) + SO4 2+ + Cu 2+ --> Cu (s) + Zn 2+ + SO4 2+ (ionic equation) Cu + Zn(s) ---> Cu (s) + Zn (net ionic)
Cu is being reduced and Zn is being oxidized, hence Zn + CuSO4 --> ZnSO4 + Cu
It is a single displacement reaction. No balancing is needed in the resulting equation. Zn + CuBr2 ----> ZnBr2 + Cu
Zn + Cu(NO3)2 --> Zn(NO3)2 + Cu
Cu(NO3)2 + Zn -> Zn(NO3)2 + Cu
Zn solid, metallicCuSO4 => becomes ionised in solution, blue colored => Cu2+aq + SO42-aqgives by reaction :Cu solid, metallicZn2+aq + SO42-aq => stays in solution, but colorlessBalanced redox-reaction:red. Zn => Zn2+ + 2 e-oxid. Cu2+ + 2 e- => CuTotal: Zns + Cu2+aq => Zn2+aq + Cus
CuSO4+Zn results in Cu+ZnSO4, but the reaction doesn`t take place the other way around CuSO4+Zn results in Cu+ZnSO4, but the reaction doesn`t take place the other way around CuSO4+Zn results in Cu+ZnSO4, but the reaction doesn`t take place the other way around
Zn(s) + CuSO4(aq) --> ZnSO4(aq) + Cu(s) The copper will plate out on the zinc. The net ionic reaction is: Zn(s) + Cu+2(aq) --> Zn+2(aq) + Cu(s)
no reaction because Cu is below Zn at electrochemical series ,so Cu can't take Zn away from its salts