No. Fluorine is an element.
Two atoms of the same element will not form a polar bond because there is no difference in electronegativity.
This molecule will be polar because it has a t-shape arrangement, and fluorine is a highly electronegative element.
No, fluorine F2 is a homonuclear molecule so there is no difference in electronegativity. This means that fluorine is a nonpolar compound.
The Molecule SF4 is Non-polar due to the fact that Fluorine is the most electronegative element in existence. Therefore the fluorine atoms evenly pull the molecule in four directions causing an even pull in the molecule and causing it to be non-polar
it has both polar bonds because F is more electronegative than Br so the electrons are shared unevenly, and it is a polar molecule because its square pyramidal geometry doesn't allow its bond dipole moments to cancel out.
NF3 is polar because, according to its Lewis structure, the molecule forms a pyramidal shape. The electronegativity of the fluorine atoms is stronger than that of the nitrogen atom, therefore causing those bonds to be polar bonds. However, if the nitrogen atom were pulled on equally from opposite directions (i.e. if there were a fourth fluorine atom) the molecule would, in fact, be non-polar. Therefore, this molecule is polar covalent, containing electrical charges.
No. Fluorine is an element. Two atoms of the same element will not form a polar bond because there is no difference in electronegativity.
This molecule will be polar because it has a t-shape arrangement, and fluorine is a highly electronegative element.
Please see http://wiki.answers.com/Q/Which_is_more_polar_fluorene_or_florenone
yes
The Molecule SF4 is Non-polar due to the fact that Fluorine is the most electronegative element in existence. Therefore the fluorine atoms evenly pull the molecule in four directions causing an even pull in the molecule and causing it to be non-polar
No, fluorine F2 is a homonuclear molecule so there is no difference in electronegativity. This means that fluorine is a nonpolar compound.
it has both polar bonds because F is more electronegative than Br so the electrons are shared unevenly, and it is a polar molecule because its square pyramidal geometry doesn't allow its bond dipole moments to cancel out.
The bonds are polar because fluorine is more elctronegative than carbon. The molecule is symmetric and therefore has no dipole moment.
NF3 is polar because, according to its Lewis structure, the molecule forms a pyramidal shape. The electronegativity of the fluorine atoms is stronger than that of the nitrogen atom, therefore causing those bonds to be polar bonds. However, if the nitrogen atom were pulled on equally from opposite directions (i.e. if there were a fourth fluorine atom) the molecule would, in fact, be non-polar. Therefore, this molecule is polar covalent, containing electrical charges.
Fluorine atoms have a covalent bond between each other to form a covalent molecule. Fluorine bonded to a metal will have ionic bonds. Fluorine bonded to a non-meatl will have polar covalent bonding.
Yeah, I think it's polar covalent, that is assuming that the F- ions are bonded to Cl. Since Fluorine has greater electronegativity, the electrons will spend more time closer to Fluorine than to Chlorine.
I-F bond is polar as the electronegativity of fluorine is more. Also the molecule is having a square pyramidal geometry with one addition lone pair being the sixth coordinate. since the dipole moments dont cancel off, the molecule is polar.