Yes, when a proton in the nucleus captures an electron from the innermost shell (K shell) it is considered a form of antibeta decay.
It emits a "beta particle," which is simply an electron. Cf-251's nucleus contains 153 neutrons. One of them spontaneously becomes a proton and an electron. The new proton bumps up its atomic number by 1, so it becomes Es-251. The overall mass is unchanged. The electron, or beta particle, is ejected from the nucleus. This is called beta decay.
Gamma rays do not release electrons; they are a form of electromagnetic radiation and do not consist of particles like alpha or beta particles. Alpha particles consist of two protons and two neutrons, while beta particles are high-energy, high-speed electrons or positrons. In radioactive decay, beta decay specifically involves the transformation of a neutron into a proton, resulting in the emission of an electron. Alpha decay involves the release of an alpha particle, which does not involve electron emission.
Beta particle( electron having nuclear origin) is emitted when a neutron decays into a proton by giving out electron. The electron produced escapes as a beta particle leaving proton in the nucleus of atom. 0n1 --> 1p1 + -1e0 ( 1e0 is the emitted beta particle) here subscripts denote charge and superscript denote mass in atomic mass unit(amu). Such neutron decay are shown by some radioactive elements. Usually when the n/p (neutron/proton) ratio is higher than required nuclei emit beta particle. Many examples of this type of decay can be given like: 6c14 --> 7N14 + -1e0 (this carbon isotope is used in carbon dating). 90Th232 + 0n1 --> 90Th232 - -1e0 --> 91Pa233 - -1e0 --> 92U233 (this reaction is used in breeder reactors for production of fissile uranium isotope)
There are several types of radioactive decay that nuclei can undergo. The primary ones are alpha decay, where the nucleus emits an alpha particle (a helium-4 nucleus), and beta decay, where the nucleus emits either an electron and electron antineutrino or a positron and an electron neutrino. There's also a decay mode called electron capture (or K capture or L capture) where the nucleus emits an electron neutrino. Any of the above types of decay generally emit a gamma ray (photon) as well.
Beta decay involves changing an up quark into a down quark (Beta+) or a down quark into an up quark (Beta-). This causes a neutron to change into a proton (Beta-) and emit a W- boson which decays into a beta particle (electron and electron antineutrino), or, with extra energy, it causes a proton to change into a neutron (Beta+) which emits a beta particle (positron and electron neutrino). Quarks are involved because protons and neutrons are comprised of quarks in sets of three, two up quarks and one down quark to form a proton, and two down quarks and one up quark to form a neutron.
Krypton-74 will most likely undergo beta decay, and the type of beta decay an observer will encounter will be beta plus decay. A proton in the nucleus will undergo a change and become a neutron, and a positron (e+) and an antineutrino (ve) will emerge from the reaction. The krypton-74 atom will transmute into a bromine-74 atom. The equation will look something like this: 3674Kr => 3574Br + e+ + ve
Since the atomic number of Sr is less than 90, Sr undergoes beta decay. Beta decay is when the element decays into another element and a neutron actually breaks apart (sort of) into an electron and proton; the proton attaches to the other element, but the electron stays alone. Thus: 90------>90 Y+e0-1 38 Sr--->39 Y+e *there should only be one e, and the 0 and -1 should be in front, just like with the elements, but the format deletes the extra spaces so i put it like that for clarity's sake. sorry!
Beta decay is a type of radioactive decay. It comes in two "flavors" or types, and they are beta plus decay and beta minus decay. The weak interaction (or weak force, or weak nuclear force) mediates this type of decay, and it allows for a change in the nucleus of an atom. Let's look at the two types. In beta minus decay, a neutron in an atom's nucleus will be converted into a proton. This happens when one of the down quarks which make up the neutron is converted into an up quark. As the change occurs, an electron will be ejected from the nucleus along with an antineutrino. The transmutation of an atom, an element, will have taken place. The new atom will have an atomic number 1 greater than that of the original element. This is nuclear transmutation. If you're interested in the equation, it looks like this: n -> p + e- + -ve In that equation, the symbols are for the neutron, proton, electron and antineutrino, respectively. In a beta plus decay event, a proton in an atom's nucleus will be converted into a neutron. One of the up quarks in the proton will be converted into a down quark. When this change occurs, a positron will be ejected from the nucleus, along with a neutrino. An atom so affected will have its atomic number go down by 1 and it, too, will have undergone transmutation to a new element. The equation for this reaction looks like this: p -> n + e+ +ve In this equation, the symbols are for the proton, neutron, positron and neutrino, respectively. Use the links below for more information on beta decay and what happens when it occurs.
During beta decay, a neutron can turn into a proton, an electron (beta particle), and an antineutrino. This process occurs when a neutron in an atomic nucleus changes into a proton while emitting an electron and an antineutrino to conserve electric charge and lepton number.
In beta decay, we see one of two things happening. In one case, a proton in an atomic nucleus is converted into a neutron (beta minus decay) and a new element is formed with the ejection of an electron and an antineutrino. In the second case, a neutron in an atomic nucleus is converted into a proton (beta plus decay) and a new element is formed with the ejection of a positron and a nuetrino. If we were to write the formulae for these reactions we'd have to "generalize" them since we won't specify an element. But we can just pick two examples and post them. We see that carbon-14 undergoes beta minus decay to become nitrogen-14 in this equation: 614C => 714N + e- + ve The carbon-14 nucleus has a neutron within it change into a proton Then we see both a beta minus particle, an electron with high kinetic energy, and an antineutrino ejected from the nucleus. When sodium-22 undergoes beta plus decay to become neon-22, it looks like this equation: 1122Na => 1022Ne + e+ + ve The sodium-22 nucleus has a proton within it change into a neutron. We'll then see a beta plus particle, a positron (an antielectron) with high kinetic energy, and a neutrino ejected from the nucleus. That's the long and short of it. Use the link below to learn more about beta decay. It will lead you to, "What is beta decay?" here on WikiAnswers, and it has been answered.
For all practical purposes, No. However, there is a very small effect on some elements due to pressure (E.g. http://www.sciencemag.org/cgi/content/abstract/181/4105/1164), there is a small effect upon Beta Decay due to magnetic field strength, and there is an effect due to ionization.
The weak force is the one that allows a quark to turn into a different flavor of quark, thus allowing a neutron to transform into a proton, or a proton to transform into a neutron. In the case of the neutron, one of its down quarks change to an up quark, emitting a W- boson in the process. The boson is itself unstable and rapidly decays into an electron and an electron antineutrino. In the case of the proton, one of its up quarks changes into a down quark, and a W- boson appears briefly, then transforms into a positron and an electron neutrino. If any of this sound familiar, it is because this is the mechanism behind beta decay. There are two kinds of beta decay (beta plus and beta minus), and you can review them and related material by using the links below to related questions.