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In beta decay, we see one of two things happening. In one case, a proton in an atomic nucleus is converted into a neutron (beta minus decay) and a new element is formed with the ejection of an electron and an antineutrino. In the second case, a neutron in an atomic nucleus is converted into a proton (beta plus decay) and a new element is formed with the ejection of a positron and a nuetrino. If we were to write the formulae for these reactions we'd have to "generalize" them since we won't specify an element. But we can just pick two examples and post them. We see that carbon-14 undergoes beta minus decay to become nitrogen-14 in this equation: 614C => 714N + e- + ve The carbon-14 nucleus has a neutron within it change into a proton Then we see both a beta minus particle, an electron with high kinetic energy, and an antineutrino ejected from the nucleus. When sodium-22 undergoes beta plus decay to become neon-22, it looks like this equation: 1122Na => 1022Ne + e+ + ve The sodium-22 nucleus has a proton within it change into a neutron. We'll then see a beta plus particle, a positron (an antielectron) with high kinetic energy, and a neutrino ejected from the nucleus. That's the long and short of it. Use the link below to learn more about beta decay. It will lead you to, "What is beta decay?" here on WikiAnswers, and it has been answered.
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What would the balanced equation for the alpha decay of thorium 229 be?
The balanced equation for the alpha decay of thorium-229, Th-229, is: Th-229 -> Ra-225 + He-4 This equation shows that a thorium-229 nucleus undergoes alpha decay to form a radium-225 nucleus and a helium-4 particle.
What is the nuclear decay equation for hydrogen-hydrogen?
The only hydrogen isotope that undergoes any type of radioactive decay is tritium (hydrogen-3), it undergoes beta decay to become helium-3. If that's not what you were asking about, I'm confused by your question.
What is the Balanced nuclear equation for uranium 238 to plutonium 241?
U-238 undergoes neutron capture to form U-239 which decays to Np-239 and further to Pu-239. Pu-239 then undergoes beta decay to form Pu-241. The balanced nuclear equation is: U-238 + n --> U-239 --> Np-239 --> Pu-239 --> Pu-241.
What is a balanced equation for positron decay of Mercury 188?
The balanced equation for positron decay of Mercury-188 ((^{188}{80}\text{Hg})) is: (^{188}{80}\text{Hg} \rightarrow ^{188}{79}\text{Au} + e^+ + \bar{\nu_e}) where (^{188}{79}\text{Au}) is gold-188, (e^+) is a positron, and (\bar{\nu_e}) is an electron antineutrino.
What is the nuclear decay equation for copper 64?
Cu decays by either negative or positive beta emission. The equation for the negative beta decay of 64Cu is: 2964Cu --> 3064Zn + -10e where -10e represents a negative beta particle or electron. The equation for the positive beta decay of 64Cu is: 2964Cu --> 2864Ni + 10e where 10e represents a positive beta particle or positron.
What would the balanced equation for the alpha decay of thorium 229 be?
The balanced equation for the alpha decay of thorium-229, Th-229, is: Th-229 -> Ra-225 + He-4 This equation shows that a thorium-229 nucleus undergoes alpha decay to form a radium-225 nucleus and a helium-4 particle.
How do you write a balanced nuclear equation for the alpha decay of polonium -216?
Po-216- -----------------> Pb-212
What is the balanced nuclear equation for the reaction in which zirconium-97 undergoes beta decay?
The equation for the beta decay of 137Cs:55137Cs --> 56137Ba + -10e where the e is a negative beta particle or electron.
What is The Balanced Nuclear Equations For The Alpha Decay Of Radium-226?
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
How do you write a balanced nuclear equation for the formation of polonium-206 through alpha decay?
If radon-210 undergoes alpha decay, it will produce the alpha particle (which is a helium-4 nucleus) and polonium-206. The equation looks like this: 86210Ra => 24He + 84206Po You'll note that in the balanced nuclear equation, the atomic numbers, which are the subscripts, balance on both sides of the equation (86 = 2 + 84). The atomic masses, which are the superscripts, also balance on both sides of the equation (210 = 4 + 206).
What shows a balanced nuclear equation for the beta decay pf potassium-42?
The balanced nuclear equation for the beta decay of potassium-42 is: ^42K -> ^42Ca + e^- + νe
What is the balanced equation for the alpha decay of radium 228?
224
How do you write a balanced nuclear equation to describe the beta decay of Sulfur?
For nuclear decay, you must also specify what isotope you are talking about. Just saying "Sulfur" simply isn't enough information.
What is the balanced nuclear equation for the alpha for radium-226?
When radium-226 undergoes alpha decay, it becomes radon-222. We write the equation like this: 88226Ra => 24He + 86222Rn Here we see the alpha particle written as a helium-4 nucleus, which is, in point of fact, what it is. Notice that the numbers that are subscripted are equal on both sides of the equation, and the superscripted numbers are as well. They must balance for your equation to be correct.
What is the nuclear equation for the decay of radium 226?
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
What is the balanced nuclear equation for the alpha decay of thorium 230?
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
What is the nuclear decay equation for hydrogen-hydrogen?
The only hydrogen isotope that undergoes any type of radioactive decay is tritium (hydrogen-3), it undergoes beta decay to become helium-3. If that's not what you were asking about, I'm confused by your question.
