The equation for the positive beta decay of 188Hg is:
80188Hg --> 79188Au + 10e
where e indicates a positron or positive beta particle.
The equation for alpha decay of mercury-201 is: ^201Hg -> ^197Au + ^4He This means that mercury-201 decays into gold-197 and helium-4 by emitting an alpha particle.
The balanced equation for the alpha decay of thorium-229, Th-229, is: Th-229 -> Ra-225 + He-4 This equation shows that a thorium-229 nucleus undergoes alpha decay to form a radium-225 nucleus and a helium-4 particle.
There are three beta decay modes for 40K, and so three equations. The equation for the negative beta decay of 40K: 1940K --> 2040Ca + -10e where the -10e represents a beta particle or electron. The equation for the positive beta decay of 40K: 1940K --> 1840Ar+ 10e where the 10e represents a positive beta particle or positron. The equation for the decay of 40K by electron capture is:1940K + -10e --> 1840Ar + ve
A positron is the antiparticle of the electron. We write the electron as e- as it is negatively charged. We write e+ or β+ for the positron. The latter symbol uses the Greek letter beta as positron emission is one of the two forms of the radioactive decay known as beta decay. Links can be found below.
There is technically no such thing as positron decay. It's a misnomer. The nuclear decay process wherein a positron is emitted from a decaying nucleus is called positron emission or beta plus decay. A link is provided below that question and its answer.
The equation for the beta decay of 17F: 917F --> 817O+ 10e + ve where the 10e is a positive beta particle or positron.
The equation for alpha decay of mercury-201 is: ^201Hg -> ^197Au + ^4He This means that mercury-201 decays into gold-197 and helium-4 by emitting an alpha particle.
The balanced nuclear equation for the beta decay of potassium-42 is: ^42K -> ^42Ca + e^- + νe
224
The equation for the positive beta decay of 40K: 1940K --> 1840Ar + 10e where the e is a positive beta particle or positron.
The nuclear decay equation for the decay of selenium-75 (75Se) by beta decay is: ( ^{75}{34}Se \rightarrow ^{75}{35}Br + e^- + \overline{\nu_e} ) This equation represents the transformation of a selenium-75 nucleus into a bromine-75 nucleus, an electron, and an electron antineutrino.
The balanced nuclear equation for the alpha decay of thorium-230 is: ^230Th → ^226Ra + ^4He
There are two ways 174Ir can decay, alpha and positive beta, so there are two different equations. The equation for the alpha decay of 174Ir is: 77174Ir --> 75170Re + 24He representing the alpha particle as a helium nucleus. The equation for the beta+ decay of 174Ir is: 77174Ir --> 76174Os + 10e + ve wher 10e represents a positive beta particle or positron.
If oxygen-16 was to undergo positron emission (beta plus decay), a proton in its nucleus would transform into a neutron (mediated by the weak force). The oxygen-16 would become nitrogen-16, and we'd see a positron and a neutrino appear. The equation might look like this: 816O => 716N + e+ + ve It is easy to write a balanced nuclear equation for any nuclide undergoing positron emission. Note the subscript numerals at the beginning of each element. That's the atomic number of that element. The superscript numerals are the atomic mass of the nuclide. When beta plus decay occurs, nuclear transformation takes place. The atomic number of the element goes down by one, and one element becomes another element. The subscripted numerals will reflect that decrease of one, and the atomic mass (the superscripted numerals) will remain the same. Note the last two factors in the equation, as they are the positron and the neutrino, respectively. That's the long and short of the beta plus decay of O-16, as asked. We'll add, however, that oxygen-16 is a stable isotope of oxygen. It does not undergo beta decay, but for the sake of argument, it did here. And with the results shown. By the way, it is oxygen-15 that is the radioactive isotope of oxygen that will undergo beta plus decay. You'll find links below for more information.
The balanced equation for the alpha decay of thorium-229, Th-229, is: Th-229 -> Ra-225 + He-4 This equation shows that a thorium-229 nucleus undergoes alpha decay to form a radium-225 nucleus and a helium-4 particle.
The equation for the beta decay of 165Ta is: 73165Ta --> 72165Hf + 10e + ve where the e is a positive beta particle or positron.
There are three beta decay modes for 40K, and so three equations. The equation for the negative beta decay of 40K: 1940K --> 2040Ca + -10e where the -10e represents a beta particle or electron. The equation for the positive beta decay of 40K: 1940K --> 1840Ar+ 10e where the 10e represents a positive beta particle or positron. The equation for the decay of 40K by electron capture is:1940K + -10e --> 1840Ar + ve