Cu decays by either negative or positive beta emission.
The equation for the negative beta decay of 64Cu is:
2964Cu --> 3064Zn + -10e
where -10e represents a negative beta particle or electron.
The equation for the positive beta decay of 64Cu is:
2964Cu --> 2864Ni + 10e
where 10e represents a positive beta particle or positron.
In beta decay, we see one of two things happening. In one case, a proton in an atomic nucleus is converted into a neutron (beta minus decay) and a new element is formed with the ejection of an electron and an antineutrino. In the second case, a neutron in an atomic nucleus is converted into a proton (beta plus decay) and a new element is formed with the ejection of a positron and a nuetrino. If we were to write the formulae for these reactions we'd have to "generalize" them since we won't specify an element. But we can just pick two examples and post them. We see that carbon-14 undergoes beta minus decay to become nitrogen-14 in this equation: 614C => 714N + e- + ve The carbon-14 nucleus has a neutron within it change into a proton Then we see both a beta minus particle, an electron with high kinetic energy, and an antineutrino ejected from the nucleus. When sodium-22 undergoes beta plus decay to become neon-22, it looks like this equation: 1122Na => 1022Ne + e+ + ve The sodium-22 nucleus has a proton within it change into a neutron. We'll then see a beta plus particle, a positron (an antielectron) with high kinetic energy, and a neutrino ejected from the nucleus. That's the long and short of it. Use the link below to learn more about beta decay. It will lead you to, "What is beta decay?" here on WikiAnswers, and it has been answered.
148/64 Gd ---> 144/62 Sm + 4/2 He (apple executive)
50 grams to 12.5 grams is a reduction of 0.75, or an ending amount of 0.25. That is two half-lives, or twenty years, in this case. The equation of half-life is ... AT = A0 2(-T/H) ... where A0 is the starting activity, AT is the ending activity at time T, and H is the half-life at units of T.
dr/dt=(-64/5)(G^3/c^5)(m1*m2)((m1+m2)/r^3) t=r^4*[15*5/(64*16*4)]*[(c^5/G^3)/(m1*m2(m1+m2))] => t = (60*10^3)^4*(75/4096)*((3*10^8)^5/((6.673*10^-11)^3)/((1.4*1.989*10^30)^2*(2*1.4*1.989*10^30)) => t = (6)^4*(75/4096)*((3)^5/((6.673)^3)/((1.4*1.989)^2*(2*1.4*1.989))*10^(16+40+33-60-30)
After 1.2 years, half of the 64 mg of radioactive isotopes decays, leaving 32 mg. After 6 years, another half-life period of 1.2 years occurs five times, with each decay halving the remaining amount. Therefore, after 6 years, the amount present will be (64 \text{ mg} \times \left(\frac{1}{2}\right)^5 = 1 \text{ mg}).
The constant factor that each value in an exponential decay pattern is multiplied by the next value. The decay factor is the base in an exponential decay equation. for example, in the equation A= 64(0.5^n), where A is he area of a ballot and the n is the number of cuts, the decay factor is 0.5.
145/62 sm is the daughter element in the above equation.
In beta decay, we see one of two things happening. In one case, a proton in an atomic nucleus is converted into a neutron (beta minus decay) and a new element is formed with the ejection of an electron and an antineutrino. In the second case, a neutron in an atomic nucleus is converted into a proton (beta plus decay) and a new element is formed with the ejection of a positron and a nuetrino. If we were to write the formulae for these reactions we'd have to "generalize" them since we won't specify an element. But we can just pick two examples and post them. We see that carbon-14 undergoes beta minus decay to become nitrogen-14 in this equation: 614C => 714N + e- + ve The carbon-14 nucleus has a neutron within it change into a proton Then we see both a beta minus particle, an electron with high kinetic energy, and an antineutrino ejected from the nucleus. When sodium-22 undergoes beta plus decay to become neon-22, it looks like this equation: 1122Na => 1022Ne + e+ + ve The sodium-22 nucleus has a proton within it change into a neutron. We'll then see a beta plus particle, a positron (an antielectron) with high kinetic energy, and a neutrino ejected from the nucleus. That's the long and short of it. Use the link below to learn more about beta decay. It will lead you to, "What is beta decay?" here on WikiAnswers, and it has been answered.
The equation for the radioactive decay of Zr-95 (zirconium-95) can be expressed using the decay constant (λ) in the exponential decay formula: ( N(t) = N_0 e^{-\lambda t} ), where ( N(t) ) is the quantity of Zr-95 remaining at time ( t ), ( N_0 ) is the initial quantity, and ( \lambda ) is the decay constant specific to Zr-95. Zr-95 has a half-life of approximately 64 days, which can also be used to derive λ using the relationship ( \lambda = \frac{\ln(2)}{t_{1/2}} ).
Its a radioactive isotope of copper with a half-life of about 12 hrs. It doesn't really have a specific name but to differentiate it from 'normal' copper it's called 'Copper-64' or 'Cu-64'
Copper is a metal element. Mass number of it is 64.
It is: 4s = 64
Copper-63 is an isotope of copper with 29 protons and 34 neutrons. It is a stable isotope of copper found in trace amounts in nature. Copper-63 is used in various applications, including in nuclear medicine and scientific research.
Copper is a meta element. Atomic mass of it is 64.
Copper is a metal element. There are 29 electrons in a single atom.
64 times 3.125 = 200
The ratio of mass of copper to oxygen in the sample is 4:1. This is determined by dividing the mass of copper (64 g) by the mass of oxygen (16 g).