No! Looks like half a combustion reaction and I do not mean the half reaction method.
C2H6O + 3O2 -> 2CO2 + 3H2O
Q: 2C2H6 plus and ?O2 yields 4CO2 plus 6H2OFirst balnce this equation for oxygen (?) (Carbon and Hydrogen are already correctly balanced): right sided O counting 4x2 + 6x1 = 14, so left sided there should be also 14 atoms O or 14/2 = 7 moleecules O22C2H6 + 7O2 --> 4CO2 + 6H2OThen divide both sides by 7 and multiply by 5 (7*5/7 O2 and 4*5/7 CO2) to find -->A: 5 mole O2 will yield (20/7=) 2.86 mole CO2
C2H6O + O2 = C2H4O2 + H2O is balanced but not sure if this is what would happen
2h2o -> 2h2 + o2
2H2O2 ==> 2H2O + O2 the equation is balanced
2NO + O2 --> NO2 is not balanced. There are two nitrogen atoms on the left and only one on the right. There are four oxygen atoms on the left and only one on the right. The correct balanced equation is 2NO + O2 --> 2NO2.
The complete combustion of ethanol in oxygen proceeds according to the balanced equation C2H6O + 3 O2 -> 2 CO2 + 3 H2O.
The chemical equation is:C2H5OH + O2 = 2 CO2 + 3 H2O
Q: 2C2H6 plus and ?O2 yields 4CO2 plus 6H2OFirst balnce this equation for oxygen (?) (Carbon and Hydrogen are already correctly balanced): right sided O counting 4x2 + 6x1 = 14, so left sided there should be also 14 atoms O or 14/2 = 7 moleecules O22C2H6 + 7O2 --> 4CO2 + 6H2OThen divide both sides by 7 and multiply by 5 (7*5/7 O2 and 4*5/7 CO2) to find -->A: 5 mole O2 will yield (20/7=) 2.86 mole CO2
C2H6O + O2 = C2H4O2 + H2O is balanced but not sure if this is what would happen
Balanced equation. C2H6O + 3O2 --> 2CO2 + 3H2O 0.274 moles C2H6O (2 moles CO2/1 mole C2H6O) = 0.548 moles carbon dioxide produced ============================
No. It would have to be H2O2 - H2 = O2 in order to be balanced.
2h2o -> 2h2 + o2
2H2O2 ==> 2H2O + O2 the equation is balanced
2Sr + O2 -> 2SrO Now it is.
The balanced equation is: CH4 + 2 O2 → CO2 + 2 H2O
yes they are balanced
C2H6O + 3 O2 = 2 CO2 + 3 H2O