No, the chemical equation is not balanced. The correct balanced equation is 2SO2 + O2 → 2SO3.
keq=[SO3]2[O2] [So3]2
An incorrect interpretation of this balanced equation could be that the reactants are sulfur (S) and sulfur dioxide (SO2) combining to form sulfur trioxide (SO3). This is incorrect as the reactants are actually sulfur dioxide (SO2) and oxygen (O2) combining to form sulfur trioxide (SO3).
1,8 moles of oxygen are necessary.
To determine the number of grams in 2.80 moles of (NH4)2SO3, you need to multiply the molar mass of (NH4)2SO3 by the number of moles. The molar mass of (NH4)2SO3 is 132.14 g/mol, so 2.80 moles of (NH4)2SO3 would be equal to 2.80 moles x 132.14 g/mol = 369.392 grams of (NH4)2SO3.
Increasing the concentration of either SO2 or O2 would drive the reaction towards the formation of more SO3, resulting in an increase in the concentration of SO3. Increasing the temperature, however, would cause the greatest increase in the concentration of SO3 as it favors the forward reaction which produces more SO3.
The equation FeSO4 = Fe2O3 + SO2 + SO3 is not balanced. To balance it, one possible balanced equation could be: 2FeSO4 = Fe2O3 + 2SO2 + 2SO3.
Its balancing is very simple, 2SO2 + O2 = 2SO3
SO2 + H20 --> H2SO3 sulphurous acid is not very stable though # The forest school, the forest school is wonderful the forest school is wonderful its filled with beer and Viagra the forest school is wonderful!!! #
The chemical equation for the reaction of sulfur and oxygen to form sulfur trioxide is: 2S + 3O2 -> 2SO3
The balanced chemical equation for the reaction is 2SO2 + O2 -> 2SO3. This means that for every 1 mole of O2 consumed, 2 moles of SO3 are produced. Therefore, 1.32 moles of O2 would produce 2.64 moles of SO3.
Sulphur burns in Oxygen to form Sulphur dioxide in the following reaction: S+O2=SO2 Sulphur dioxide has a capability of reacting with oxygen to form Sulphur trioxide in the following reaction: 2SO2+O2=2SO3 By Prince Sambo Metallurgist
This is not a straight formula. First, 2SO2 + O2 -> 2SO3 Then,SO3 + H2O -> H2(SO4)This is the equation for sulfur dioxide and oxygen gas creating sulfuric acid ... mostly useful when studying acid rain!
adding SO2
K2CO3 (s) → K2O (s) + CO2 (g)2SO3 (g) → 2SO2 (g) + O2 (g) CaCO3 (s) → CaO (s) + O2 (g)
keq=[SO3]2[O2] [So3]2
S8 + 12O2 = 8SO3.Since there are 8 sulfur on the left, you must have 8 on the right, so 8SO3. Now you have 24 oxygen on the right, so you need 24 on the left. Multiplying O2 by 12 balances it.
Yes, the reaction 2SO2 + O2 -> 2SO3 is a combustion reaction. This is because combustion reactions typically involve a fuel (SO2) reacting with oxygen (O2) to form a combustion product (SO3) with the release of heat and light energy.