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The time constant is equivalent to 1/(R*C); since C (the capacitance of the capacitor) is not changing, yes, the charging and discharging times will be the same, provided the Thevenin resistance is the same as well - if you charge a capacitor using a AA battery, then remove the battery, and discharge through a resistor, you have changed the Thevenin resistance, thus the discharge time will NOT be equal.

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Q: Is capacitor discharging time is equal with charging time or not?
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The effect of resistance on the rate of charging or discharging a capacitor?

If the resistance is in series with the capacitor, the charge/discharge time is extended.


What can you say to charging and discharging capacitor?

A capacitor will charge at a set time of 63% for one time constant and will continue to do so until fully charged which mathematically will never happen. therefore in the industry a 5 time interval is considered as fully charged.


What is the effect on charging and discharging times if the capacitance is increased?

The charging and discharge time increases. R*C=T


Why high value resistor should be connected in series with capacitor during charging or discharging process?

A resistor is used to limit current flow through a capacitor.If you did not use the resistor, you could potentially create large currents through the capacitor, damaging it. Capacitors do have current limit ratings - check the specification sheet for the capacitor.Also, in the case of an electrolytic capacitor, if it is generally in a discharged state then it is necessary from time to time to reform it. That process involved slowly charging it, i.e. through a resistor, and then letting it discharge by itself with no or little load. The resistor protects both the capacitor and the voltage source in the case that the capacitor might be shorted.


In a tank circuit why can be the energy across the inductor and that of the capacitor not be equal?

When an LC tank is excited at the resonant frequency, the energy across each will be equal (but not necessary equal at a given moment in time). If excited at a frequency other than the resonant frequency, the impedance of the inductor (wjL) and capacitor (1/wjC) will not be equal, therefore energy across each will be different.

Related questions

Define capacitive time constant in terms of charging and discharging?

The product of resistance and capacitance is referred to as the time constant. It determines rate of charging and discharging of a capacitor.


The effect of resistance on the rate of charging or discharging a capacitor?

If the resistance is in series with the capacitor, the charge/discharge time is extended.


Why you use CRO to observe the charging and discharging current of capacitor?

using CRO we can measure the rise time and fall time of the capacitor for further studies


Why is the charging time of a capacitor lower than the discharging time?

It's not. If the series resistance doesn't change, then the charge and discharge rates are the same.


What can you say to charging and discharging capacitor?

A capacitor will charge at a set time of 63% for one time constant and will continue to do so until fully charged which mathematically will never happen. therefore in the industry a 5 time interval is considered as fully charged.


What is a voltage time base generator?

I believe you are referring to a piece of test equipment also known as a "function generator." It generates a voltage equal to some function of time. The most basic models will produce sine, square, and sawtooth waves at different frequencies, but the more expensive models will do all kinds of waves. these voltage time base generators are those which are used to generate voltage linearly with time. by using the transistor as a switch and using a capacitor we can get the ramp out put. here the working would be the capacitor charging when the transistor is off and discharging when the transistor is on. the discharging time is very less compared to the charging time. when the capacitor charges voltage across it increases exponentially and we get a wave which increases linearly with time.


Explain the Potential across the resistor during the charging and discharging process of the capacitor?

The voltage across a capacitors given as a time constant t= 63% the resistor value multiply buy capacitor value. it doesn't matter if it goes more or less negative it will follow this function


What is the effect on charging and discharging times if the capacitance is increased?

The charging and discharge time increases. R*C=T


Why is discharging slower than charging in a capacitor filter?

Look closely at the circuit. If discharging is slower than charging, then there must be less current available for discharging. The equation of a capacitor is... dv/dt = i/c which means that the slope of the voltage is proportional to the current and inversely proportional to the capacitance. This does not matter if it is a charging or a discharging situation. For example, one amp of current into one farad of capacitance will be one volt per second, and negative one amp of current into (out of) that same one farad capacitance will be negative one volt per second. You don't give a lot of information in the question, but it sounds like you are analyzing the filter in a rectifier. The charge path is through the diode, which is a low impedance, high current, circuit, while the discharge path is only through the load. This would explain, in one case, why the discharge time is greater than the charge time.


What is the act of recovering energy from Capacitor?

A: It is called discharging a capacitor. The charge will follow the rules of a time constant set up by the series resistor and the capacitor. 1 time constant 63% of the charge will be reached and continue at that rate.


Why the capacitor time period formula is given as t equals RC?

-- The quantity 'RC' has the physical dimensions of Time. -- If the capacitor is charging through a resistor, then 'RC' is the time it takes to charge up to (1 - 1/e) of the voltage it still has to go to become fully-charged. -- If the capacitor is discharging through a resistor, then 'RC' is the time it takes to discharge to 1/e of its present voltage. -- ' e ' is the base of natural logarithms, approximately 2.71828... -- 'RC' is called the 'time constant' of the resistor/capacitor combination.


Why high value resistor should be connected in series with capacitor during charging or discharging process?

A resistor is used to limit current flow through a capacitor.If you did not use the resistor, you could potentially create large currents through the capacitor, damaging it. Capacitors do have current limit ratings - check the specification sheet for the capacitor.Also, in the case of an electrolytic capacitor, if it is generally in a discharged state then it is necessary from time to time to reform it. That process involved slowly charging it, i.e. through a resistor, and then letting it discharge by itself with no or little load. The resistor protects both the capacitor and the voltage source in the case that the capacitor might be shorted.