Ch3cooh
CH3COOH and CH3COO- CH3NH2 and CH3NH2H+
Dissolving in water = splitting in ionsCH3COONH4 --> CH3COO- + NH4+CH3COO-, acetate is a weak base: CH3COO- + H2O CH3COOH + OH-NH4+, ammonium is a weak acid: NH4+ + H2O NH3 + H3O+Totally in water: CH3COO- + NH4+ CH3COOH + NH3 and 2H2O H3O+ + OH-
Buffer
In general, a buffer system can be represented by writing a salt followed by slash and an acid or conjugate base followed by slash and an acid like salt/acid or conjugate base/acid. Thus, the sodium acetate-acetic acid buffer system can be written asCH3COONa/ CH3COOH or CH3COO-/CH3COOHSimilarly, ammonia-ammonium chloride buffer system can be represented asNH3 / NH4+Note that NH4+ is an acid and NH3 is a conjugate base according to Lewry-Bronsted concept.
Ch3cooh
BC
Buffers are made out of what are called weak acids or weak bases. Mixtures of CH3COOH and CH3COONa can act as buffers because they don't break apart completely in solution like HCl and NaCl. As the CH3COOH and CH3COONa are in solution they keep the pH constant by either donating or accepting protons because they don't act like strong acids or bases. HCl is known as a strong acid where the hydrogen disassociates completely from the chloride. NaCl is not a buffer because it dissolves completely as welll
Solutions that resist change in pH when added to a strong acid or base are known as buffer solutions.
CH3COOH + NaHCO3 = CH3COONa + CO2 + H2O
CH3COOH + NaOH = CH3COONa + H2O
CH3COOH+NaOH=CH3COONa+H2O
the products are CH3COOH + NaOH ------CH3COONa + H2O
CH3COOH + NaHCO3 ---> CH3COONa + H2O + CO2
nahco3 + ch3cooh --> co2 + CH3COONa + h2oNote: it is CH3COONa (sodium acetate) and not na2co3(sodium carbonate) as stated in the question above
CH3COOH + NaHCO3 --> CH3COONa + H2O + CO2
CH3COOH + NaOH -----> CH3COONa + H2O(Ethanoic acid) (Sodium hydroxide) (Sodium Acetate) (Water)