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Is chromium (Ii) sulfate ionic

Updated: 9/25/2023
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Q: Is chromium (Ii) sulfate ionic
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Related questions

What is CsSO4?

chromium(II) sulfate


What type of chemical bond is Chromium sulfate?

Chromium sulfate typically forms ionic bonds. In ionic bonding, one atom donates electrons to another atom, resulting in the formation of charged ions that are attracted to each other.


What is the stock system name for CrSO3?

iron(II


What is the name of the ionic compound CrF2?

Chromium II fluoride


What is the formula of chromium II sulfate?

Annon:The chemical formula of chromium II sulfate is CrSO4.Miki-San-X: ActuallySince this is probably Ionic naming since it starts with a metal and ends with a non metal you would take chromium (II) Sulfate and cross them-Like so-Start:Cr(II) SO4 (-2)We know that sulfate is SO4 with a -2 superscript and that chromium is a transition metal, but that it has a positive charge to counteract the negative charge of the -2.You will drop the charge and cross them-Cr2(SO4)2since you brought the -2 from the sulfate down to the chromium it becomes positive 2 because you dropped the charge before crossing. The reason you put the (SO4) in parenthesis is because you cannot, in a problem like this, have 42 next to your polyatomic ion. You have TWO of that ion, NOT 42.Hope I helped


Is copper II sulfate pentahydrate an ionic compound?

Yes it is


What is the name for the ionic compound for FeSO4?

Iron (II) sulfate


Does CuSO4 have an ionic or covalent bond?

Copper (II) sulfate is ionically bonded.


What is the name of the ionic compound CrCl3?

Chromium (III) chloride


What is the chemical formula for chromium (111) sulfate?

The chemical formula for chromium (III) sulfate is Cr2(SO4)3.


What type of bond is ferrous sulfate?

Fe 2+andSO4 2-form the ionic bond,Ferrous sulfate, FeSO4, also know as iron II sulfate.


What is the correct formula for the ionic compound formed between chromium and chloride?

Chromium (II) chloride = CrCl2Chromium (III) chloride = CrCl3 Chromium (IV) chloride = CrCl4