Of the 'balanced' what?
yes.
noAnswer'Power factor' is a quantity associated with alternating-current systems, and does not apply to direct-current systems'.
First of all, you can only measure power factor of a three-phase load, provided that it is balanced load. The power factor can then be found by determining the cosine of the phase angle, using the following equation:tan (phase angle) = 1.732 ((P2-P1)/(P2+P1))...where P1 and P2 are the readings of the two wattmeters.
yes, it is possible. in fact in power systems all the generators do not run with same power factor.
When looking at power factor, it is the ratio of watts (true power) to VA. The power factor is how we measure power systems. A person with a low power factor like .26 will have a higher electricity bill.
not possible. power factor is an cosine angle between current and voltage...
Because a dynamometer is used to measure the mechanical power output of a motor or engine. There are ways of measuring the power factor directly, for example use a plug-in power and energy monitor.
I am assuming that you really want to use ammeters to measure power in a balanced 3 phase system. (hope you are not meaning 3 watt meter method) Power in Watt in a three phase system is equal to 1.73 x line voltage x line current x power factor. You need to know line voltage, power factor also in addition to current to compute the power. If the system is balanced then actually you do not need to connect ammeters in all three lines. One ammeter reading will do.
A resistor doesn't have a power factor. However, if a circuit is pure resistance in nature the power factor will be one when a voltage is applied and a current flows in the circuit. The power factor is a measure of the relative phases of the current and voltage in a circuit.
The power factor depends on the properties of the load, and if any power factor correction is done it has to happen at the load, so that the current in the transmission lines is reduced. Correcting the power factor at the sending end fails to address the problem.
Yes. The wattmeter's current coil will have to be connected into one of the line conductors, and its voltage coil between that same line conductor and the neutral point of the load. Connected this way, the wattmeter's voltage coil is measuring one of the three phase voltages (line-to-neutral voltage) while its current coil is measuring the corresponding phase current (for a 4-wire system, the phase current = line current). The power factor (cosine of the phase angle) is accounted for automatically within the wattmeter. So the wattmeter will measure the true power (in watts) of one phase. The total power, therefore, will be 3x the wattmeter reading -providing, of course, that the load is balanced (i.e. each phase is identical). WebRep currentVote noRating noWeight
A three-phase 'unbalanced' system refers to the load, as the supply voltages are unaffected by load. So the phase-angle and, therefore, the power factor of each phase will be different -i.e. there will be three different power factors.