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You do have a right of self defence. But they have to hit you first
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∙ 15y ago
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Why did Molly Pitcher fight?
cos her husband died
What is cos in a math problem?
Its a ratio in a right angle triangle, cos angle = adjacent / hypotonuse.
Do dwarfs have huge knobs cos your wife says they do?
Yes because she said so. You never fight with your wife cause you are either wrong or when youre right they get pissed and you still lose.
How would you prove left cosA plus sinA right times left cos2A plus sin2A right equals cosA plus sin3A?
You need to make use of the formulae for sin(A+B) and cos(A+B), and that cos is an even function: sin(A+B) = cos A sin B + sin A cos B cos(A+B) = cos A cos B - sin A sin B cos even fn → cos(-x) = cos(x) To prove: (cos A + sin A)(cos 2A + sin 2A) = cos A + sin 3A The steps are to work with the left hand side, expand the brackets, collect [useful] terms together, apply A+B formula above (backwards) and apply even nature of cos function: (cos A + sin A)(cos 2A + sin 2A) = cos A cos 2A + cos A sin 2A + sin A cos 2A + sin A sin 2A = (cos A cos 2A + sin A sin 2A) + (cos A sin 2A + sin A cos 2A) = cos(A - 2A) + sin(A + 2A) = cos(-A) + sin 3A = cos A + sin 3A which is the right hand side as required.
Who are the easiest boss in AQworlds?
Probably the princess on the red dragon in the Newbie area. She only has 542 health and she's EASY! That's 'cos she's a newbie boss- you have to fight her right at the beginning.
Why children have the right to play?
cos kids are awsome
Who was general cos?
A Mexican general who helped santa Anna fight the Texans in the TExan Revolution
How would you find out the sin tan and cos of right angle triangle?
sin, tan and cos can be defined as functions of an angle. But they are not functions of a triangle - whether it is a right angled triangle or not.
What is the relationship between the cos and sin of the non 90 degree angles in a right angle triangle?
sin θ = cos (90° - θ) cos θ = sin (90° - θ)
Who would win in a fight between optimus prime and a gigantosaurus?
i think optimus would cos he has all the guns
What is the value of h in a right angled triangle with 31° and 15cm?
Following the symbols in the image: Assuming 15cm corresponds to a (the line adjacent to the angle), then you need to use the cosine formula cos(ø) = a/h cos(31º) = 15cm/h h*cos(31º) = (15cm/h) * h h*cos(31º) = 15cm * 1 h*cos(31º)/cos(31º) = 15cm/cos(31º) h*1 = 15cm/cos(31º) h = 16.398
Cos plus tansin equals sec?
Start on the left-hand side. cos(x) + tan(x)sin(x) Put tan(x) in terms of sin(x) and cos(x). cos(x) + [sin(x)/cos(x)]sin(x) Multiply. cos(x) + sin2(x)/cos(x) Make the denominators equal. cos2(x)/cos(x) + sin2(x)/cos(x) Add. [cos2(x) + sin2(x)]/cos(x) Use the Pythagorean Theorem to simplify. 1/cos(x) Since 1/cos(x) is the same as sec(x)- the right-hand side- the proof is complete.
