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Is it true that an example of a stress on an equilibrium is the increase of pressure in a closed system when the pressure of a reactant gas is increased from 1.0 ATM to 2.0 ATM?
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∙ 12y ago
false
Wiki User
∙ 12y ago
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How does an equilibrium reaction respond to the addiof extra reactant?
The concentration or activity of the product(s) will increase, and if there is at least one other reactant than the added one that is required for the completion of the reaction, the concentration of such an unadded reactant will decrease. (If there were no available unadded reactant, the reaction would not technically have been in equilibrium at the start, even though it may have reached a steady state that can persist for a long time in the absence of changed conditions.)
What will be the consequences of adding or removing a reactant or aproduct from a reaction that is at dynamic equilibrium?
if reaction is at equ. then adding product will cause reaction to proceed forward and product will increase and removing product will do the same while removing reactant will cause reactn 2 proced bakward and reactant will increase and adding product wl do the same it is in accordnc wth LeChateliars principle
What will happen to a weak acid dissociation equilibrium if more reactants were added?
Concentration of products would increase in order to attain equilibrium in the system again.For example:H2CO3 --> H+ + HCO3-K= ([H+][žHCO3-])/([H2CO3])K is constant for this process, so if you increase the concentration of reactants (H2CO3), in order for K to stay the same, concentration of products (H+, HCO3-) would also have to increase.It's part of Le Chatelier's principle: "If a chemical system at equilibrium experiences a change in concentration, temperature, volume, or partial pressure, then the equilibrium shifts to counteract the imposed change and a new equilibrium is established."So, in your case, adding more reactant would cause equilibrium to shift to the right (toward products), and therefore, their concentration would increase so that new equilibrium could be established.
When equilibrium shifts to the reactants in response to stress how is the equilibrium position changed?
When the concentration increases, the equilibrium shifts away from the substance. Equilibrium is based on the molarity of the reactants. Increasing concentration increases the amount of that reactant in the solution.
Hat will happen when a reactant is added to a system at equilibrium?
The concentrations of reactants and products are modified.
Why does changing the concentration of reactant shift the equilibrium?
Le Chatlier's PrincipleIf an equilibrium reaction is occurring and some reactant from either side of the equilibrium is added, the reaction goes in a direction that is to oppose the addition of a reactant. For example. In the equilibrium of CO2 + H2O = H2CO3, if more CO2 is added then the equilibrium shifts in such a way that this change is opposed so more H2CO3 is produced. For more information, research Le Chatlier's Principle.
How does an equilibrium reaction respond to the addiof extra reactant?
The concentration or activity of the product(s) will increase, and if there is at least one other reactant than the added one that is required for the completion of the reaction, the concentration of such an unadded reactant will decrease. (If there were no available unadded reactant, the reaction would not technically have been in equilibrium at the start, even though it may have reached a steady state that can persist for a long time in the absence of changed conditions.)
What will happen when a reactant is added to a system?
The equilibrium is not maintained.
What will be the consequences of adding or removing a reactant or aproduct from a reaction that is at dynamic equilibrium?
if reaction is at equ. then adding product will cause reaction to proceed forward and product will increase and removing product will do the same while removing reactant will cause reactn 2 proced bakward and reactant will increase and adding product wl do the same it is in accordnc wth LeChateliars principle
What will happen to a weak acid dissociation equilibrium if more reactants were added?
Concentration of products would increase in order to attain equilibrium in the system again.For example:H2CO3 --> H+ + HCO3-K= ([H+][žHCO3-])/([H2CO3])K is constant for this process, so if you increase the concentration of reactants (H2CO3), in order for K to stay the same, concentration of products (H+, HCO3-) would also have to increase.It's part of Le Chatelier's principle: "If a chemical system at equilibrium experiences a change in concentration, temperature, volume, or partial pressure, then the equilibrium shifts to counteract the imposed change and a new equilibrium is established."So, in your case, adding more reactant would cause equilibrium to shift to the right (toward products), and therefore, their concentration would increase so that new equilibrium could be established.
When equilibrium shifts to the reactants in response to stress how is the equilibrium position changed?
When the concentration increases, the equilibrium shifts away from the substance. Equilibrium is based on the molarity of the reactants. Increasing concentration increases the amount of that reactant in the solution.
Hat will happen when a reactant is added to a system at equilibrium?
The concentrations of reactants and products are modified.
What does Le Châtelier's principle say about upsetting a system at equilibrium?
When a change is imposed on a system at equilibrium, the "position" of the equilibrium shifts in a direction that reduces the effects of that change. For example, if a reactant or product is added, the system shifts AWAY FROM that added component to use the excess up. If heat is added, the system shifts AWAY FROM that added energy energy to use the excess up. If the pressure on a system is increased, the system shifts toward the side with fewer gas molecules.
What will happen when a reactant is added to a system at equilibrium?
The equilibrium of the system will be upset.
What happens when reactant is added to a system at equilibrium?
The equilibrium of the system will be upset.
Does an increase in pressure at constant temperature increase the rate constant of a reversible reaction in both directions?
The rate constant is unaffected, as demonstrated by Arrhenius equation: k = Ae^(-E/RT) where A is the pre-exponential factor (constant for a particular reaction) E is the activation energy R is the molar gas constant T is the thermodynamic temperature However, when pressure is increased at constant temperature for a gaseous reversible reaction, the concentrations of every reactant and product increase by the SAME factor. Since Kp (pressure equilibrium constant) is to remain constant, it means that the position of equilibrium will shift in such a way so as to decrease the total number of moles of gaseous species. Note: This answer can be improved by proving the last statement using a general example which, due to lack of time, I skipped. (Although some people might get the logic!!!)
What would happen to a weak acid dissociation if more reactants were added?
Concentration of products would increase in order to attain equilibrium in the system again.For example:H2CO3 --> H+ + HCO3-K= ([H+][žHCO3-])/([H2CO3])K is constant for this process, so if you increase the concentration of reactants (H2CO3), in order for K to stay the same, concentration of products (H+, HCO3-) would also have to increase.It's part of Le Chatelier's principle: "If a chemical system at equilibrium experiences a change in concentration, temperature, volume, or partial pressure, then the equilibrium shifts to counteract the imposed change and a new equilibrium is established."So, in your case, adding more reactant would cause equilibrium to shift to the right (toward products), and therefore, their concentration would increase so that new equilibrium could be established.
