Yes, it is true to say that a projectile has zero acceleration at its peak.
Because the highest height, which the object will reach is known as the peak of the object's motion. The increase of the height will last, until vy = 0.,
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acceleration goes with boost of of any type of matter
a body projected upward is in rest at the top most point, but acceleration is not zero
The acceleration of cart is dependent on angle of inclination. So angle will change acceleration. mgSin(theta)
Acceleration equals the change in velocity over a period of time. a= (Vfinal- Vinitial)/t Plug in the acceleration and other information they give you. Then solve.
Acceleration is change in velocity. It is a vector, so some direction is choosen as positive and the opposite direction as negative. Then you have two possibilities;(1) the object is increasing its speed in the negative direction. (2) the object is decreasing its speed in the positive direction. Both of these give negative acceleration. For example; if up is choosen as positive then acceleration due to gravity is always negative because when a projectile is projected up with some initial velocity it decreases its speed on the way up. But on the way down its increasing its speed, in the negative direction.
Give reason for answer
No it is not because its direction is constantly changing. It is not a constant force. Force has direction as well as magintude and while it magnitude is constant its direction is not.
Give me a chance to explain what happened.If you're confused, I'll explain the directions again.When he took the stand, the defendant tried to explain the reason for his actions.
In case of uniform acceleration,the graph will be a straight line with a +ve slope ,if we are taking velocity along Y-axis and time along X-axis.hence it's slope will give u acceleration.
Because within circular motion, acceleration is constant
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You ignore the acceleration, and just give them the mass. Now, if they give you the acceleration and the applied force, you could use m = F/a.
45 degrees to the horizontal will give the maximum flight time for a projectile. If a projectile was fired at 90 degrees to the horizontal, (straight upwards) the projectile will go straight upwards (ignoring the shape, form and aerodynamic properties of the projectile). Likewise if you were to fire a projectile at 0 degrees to the horizontal, the projectile would follow said course, IF gravity was not in effect; a projectile needs some form of vertical velocity to overcome gravity. Hence why 45 degrees will give you the longest distance and consequently flight time.
give sample of word problem of acceleration
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They height y of the projectile is given by the function y = vosin(0)t + 1/2gt2, where vo is the initial velocity of the projectile, 0 is the firing angle, t is the time, and g is the acceleration of gravity (-9.81m/s2). The range x of the projectile is given by the function x = vocos(0)t. Rearranging this last equation for time yeilds t = x/(vocos(0)); this will give us the length of time the projectile takes to reach the target. Substituting this into the first equation yeilds: y = vosin(0)[x/(vocos(0))] + 1/2g[x/(vocos(0))]2 this can be simplified further but it is not necessary to do so; plugging it the x and y coordinates, the initial velocity, and the acceleration of gravity, you should be able to solve for 0, which is now the only unknown.
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