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Potassium iodide is a polar, ionic compound.

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Q: Is potassium iodide a polar covalent compound?
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Related questions

Is potassium iodide a polar molecule?

Potassium iodide isn't even a molecule. It is an ionic compound, which is in a sense polar.


What type of bond does the element Hl have?

Hydrogen iodide is not an element, but a compound made out of hydrogen and iodine. It is a polar covalent compound.


Is iodide a polar covalent?

Iodide compounds with alkali metals are considered ionic- but because of the electronegativity of Iodine, 2.66, some metals such as gallium bond to iodine with polar covalent bonds. Organic iodes such as methyl iodide, ethyl iodide are covalently bonded, (polar covalent)


Potassium iodide has polar or nonpolar bonds?

strictly polar


Is ch3oh non polar covalent or polar covalent?

Methanol is a polar covalent compound.


Is it possible for a polar covalent compound to have a lower melting point than a non-polar covalent compound?

It is not possible for the polar covalent compound to have a lower melting point than the non-polar covalent compound because they have ionic bonds.


Is potassium sulfate non polar?

Potassium Iodide is the chemical name for the molecular formula KI. Potassium forms the cation of K+ and iodine the anion of I-. Thus it is an ionic compound.


Is l2 a covalent or ionic compound?

I2 is a non-polar covalent compound.


Molecular name of hydrogen iodide?

There are a few covalent compound for hydrogen iodide. A few of the covalent compound are Antimony Tribromide, Hexaboron Silicide, Chlorine Dioxide, Hydrogen Iodide, Iodine Pentafluoride, Dinitrogen Trioxide ,Ammonia and Phosphorus Triodide.


Can a compound be covalent and polar covalent?

Yes a compound can be both if it has polar bonds that are not matched on the opposite side by the same polar bond.


What is the polarity of bonds for HI?

Hydrogen iodide has a polar covalent bond.


Is sulphur dioxide made of ionic compound?

No. sulphur dioxide has polar covalent bond and is a polar covalent compound.