No,beacuse the wall is oushing against you. For work to be done, it has to be done in the same direction.
Obviously 20 N of force, right? Since neither object goes anywhere.
Not sure if this is a real physics question... but yes, pushing against a wall is tiring even though no "work" is being done. Its isometric conditioning. Think of this: Put your hands in front of you and press them together as hard as you can for as long as you can. This will tire you out pretty quick.
when force is applied and work is done In order to accomplish work on an object there must be a force exerted on the object and it must move in the direction of the force. for example if u climb a tree u are doing work and force is applied
1) When you push an object on a flat surface work is being done against the force of friction (and air resistance). Work is calculated by the formula: Work = Force applied x distance moved in the direction of the force 2) When you push a spring to compress it, you are doing work against its stiffness In this case, Work = Force applied x 0.5 x decrease in length of spring 3) When you push something vertically upwards, you are working against gravity Here, Work = mass x earth's gravity x height raised
Surprisingly, there is actually work being done! However, if a single person's just leaning against a wall, pressing their weight actively into it, there's not enough pressure being exerted on the wall to make it move. It does experience the pressure, but the other forces of the rest of the wall pressing in on it, gravity holding it together, all push back more. As well, even if no work was truly being done against the wall, locking your arms in one spot and applying pressure to your own muscles works those muscles to fatigue.
In activity B, where you are pushing against a rock but not moving it, work is being done in its scientific meaning as the force you apply results in a displacement over time, even though the rock doesn't move. In activities A and C, no work is being done because there is either no displacement in the case of sitting still on a rock (A) or no force causing a displacement in the case of pushing a rock over a cliff (C).
Obviously 20 N of force, right? Since neither object goes anywhere.
I think yes
Not sure if this is a real physics question... but yes, pushing against a wall is tiring even though no "work" is being done. Its isometric conditioning. Think of this: Put your hands in front of you and press them together as hard as you can for as long as you can. This will tire you out pretty quick.
they move there legs
In the general sense, you aren't, but in a scientific sense, as you are holding the bucket, then you are engaged in work. So it depends on what perspective you are asking from.
The idiom "up against the wall" refers to feeling trapped, cornered, or in a difficult situation where there are no easy options or solutions available. It conveys a sense of being pressured, with limited room for movement or maneuvering.
Someone pushing against a lever.
You hit your head against a brick wall and the brick wall does not move.
when force is applied and work is done In order to accomplish work on an object there must be a force exerted on the object and it must move in the direction of the force. for example if u climb a tree u are doing work and force is applied
Work is the product of a force and the distance through which it acts in the direction of the force. In order for work to be done, the object must move in the direction of the force. If you push on a brick wall until you exhaust yourself and the wall doesn't move, you have not done any work. If you push on a box and it moves in the direction that you are pushing it, you have done work.
1) When you push an object on a flat surface work is being done against the force of friction (and air resistance). Work is calculated by the formula: Work = Force applied x distance moved in the direction of the force 2) When you push a spring to compress it, you are doing work against its stiffness In this case, Work = Force applied x 0.5 x decrease in length of spring 3) When you push something vertically upwards, you are working against gravity Here, Work = mass x earth's gravity x height raised