Quantum transition for the UV-VIS absorption refers to taking the electron transitions associated with visible and ultraviolet.
It depends on what gas you are talking about.
Chlorine gas is green. If you heat iodine to make iodine gas it is a beautiful purple. Gasses of several compounds are also visible.
Gas is only visible by having a certain color: Chlorine: greenish yellow, Iodine: purple, Bromine: redish brown. No color, not visible.
oxygen i s colorless gas because it does not appear in the visible region of uv visible spectroscopy
Carbon dioxide in its Gaseous form is not visible.
CO is a gas. It has no color
gas cap loose..
I think you are looking for the Photosphere. That is the part of a star that emits visible light.
The temperature of the layer of gas that produces the visible light of the Sun is around 5,500 degrees Celsius (9,932 degrees Fahrenheit). This layer is called the photosphere and is the visible surface of the Sun. It emits light in the visible spectrum that we see.
A fermi gas is a model from quantum mechanics first proposed by Fermi. A neutron star is said to be an example of a Fermi gas, and that would indeed be a dangerous place.
A degenerate gas is a state of matter where particles are tightly packed together and follow quantum mechanical principles. This type of gas has unique properties such as high density, low temperature, and pressure. The behavior of a degenerate gas is characterized by the exclusion principle, which states that no two particles can occupy the same quantum state. This leads to unusual behaviors such as superfluidity and superconductivity.