Line current = 1.732 x Phase CurrentCommentOnly for balanced loads.
For Single Phase, P = VI cos (theta) therefore cos(theta) = P/VI here P = Power V = voltage I = current theta = phase angle current to voltage cos(theta) = power factor For Three Phase, P = 3VI cos(theta) where V = phase voltage and I = phase current and theta = phase angle
In a balanced 3-phase system, if the three loads are star connected, the line current is equal to the load current. If the loads are delta connected, the line current is less than the load current by a factor of 1/sqrt(3).
The term, 'unbalanced system' refers to an unbalanced load. Under normal circumstances, an unbalanced load leads to unbalanced line currents. The line voltages are determined by the supply and remain symmetrical, even when the load is unbalanced. As your question refers to a 'line to neutral' voltage (i.e. a phase voltage), you must be referring to a star (wye) connected load, in which case the phase voltage (line to neutral voltage) is 0.577 (the reciprocal of the square-root of 3) times the line voltage (line to line voltage).
Negative sequence current is defined as 3I2 = (phase 1)*(1angle 0) + (phase 2)*(1angle 240) + (phase 3)*(1angle 120) Negative sequence current is seen in three phase power systems due to natural system imbalance. Also during unbalanced fault conditions such as line to line, Line to ground, and line to line to ground faults. It is not seen in purely balanced three phase faults.
A phase current is the current passing through a phase, whereas a line current is the current flowing through a line.
Because if you apply Kirchhoff's Current Law to the junction between the line current and the two phase currents, the line current is the phasor (vector) sum of two phase currents. For a balanced load (only), this works out to 1.732 x phase current.
The current is the same in the three live wires. The voltage can be described as the line voltage (phase to neutral) or the phase voltage (phase to phase) which is larger by a factor of sqrt(3). So a line voltage of 230 v corresponds to a phase voltage of 400 v.
Line current = 1.732 x Phase CurrentCommentOnly for balanced loads.
A-for star connectionE(line)=1.73E(Phase)I(line)=I(Phase)&B-for delta connectionE(line)=E(Phase)I(line)=1.73I(Phase)
A phase current is the current passing through a phase, whereas a line current is the current flowing through a line.In the case of a balanced delta-connected load, IL = 1.732 IP. In the case of a balanced star-connected load, IL = IP.For unbalanced loads, these relationships don't hold true, and must be individually calculated.
For Single Phase, P = VI cos (theta) therefore cos(theta) = P/VI here P = Power V = voltage I = current theta = phase angle current to voltage cos(theta) = power factor For Three Phase, P = 3VI cos(theta) where V = phase voltage and I = phase current and theta = phase angle
normally delta connection wired in 3 phase induction motor. during starting wiring is in Star and after running normal speed changeover to delta .beacause starting time its phase voltage equals less root3 times of line voltage ,line current and phase current equals. in Delta phase voltage and line voltage equals, and phase current equals root3 times line current
The following equation only works for a balanced three-phase load, that is, where each of the three phases is identical in all respects:P = 1.732 VL IL x power factor, where VL and IL represent line voltage and line current, respectively.For unbalanced loads, you must determine the power of each phase, using the following equation, and add them together to find the total power:Pp = VP IP x power factor, where VPand IP represent phase voltage and phase current, respectively.
A load current is a current drawn by an electrical load. In other words, it is the current flowing from the source to the load.For a single-phase system, a line current is a current flowing through the line, or 'hot', conductor, while the current through the neutral conductor is called the neutral current.For a three-phase system, the three 'hot' conductors between the load and the source are called 'lines' and, so, the currents passing through them are called 'line currents'. For a three-phase system, loads are either connected between line conductors (delta-connected system) or between each line and the neutral (star- or wye-connected system), and represent the phases -so the currents passing through the loads are called 'phase currents'.For a balanced three-phase system, the line current is 1.732 times the value of a phase current, where the phases (loads) are connected in delta. For phases (loads) connected in star (or 'wye') the line current is numerically-equal to the phase currents.
In a balanced 3-phase system, if the three loads are star connected, the line current is equal to the load current. If the loads are delta connected, the line current is less than the load current by a factor of 1/sqrt(3).
The term, 'unbalanced system' refers to an unbalanced load. Under normal circumstances, an unbalanced load leads to unbalanced line currents. The line voltages are determined by the supply and remain symmetrical, even when the load is unbalanced. As your question refers to a 'line to neutral' voltage (i.e. a phase voltage), you must be referring to a star (wye) connected load, in which case the phase voltage (line to neutral voltage) is 0.577 (the reciprocal of the square-root of 3) times the line voltage (line to line voltage).