In a balanced 3-phase system, if the three loads are star connected, the line current is equal to the load current. If the loads are delta connected, the line current is less than the load current by a factor of 1/sqrt(3).
Just by using the formula 1.732 x V x I x cos theeta where
V the line voltage,
I the line current
cos theeta the power factor,
we can arrive the energy/power
By dividing the individual phase voltage by its corresponding phase impedance.
In a single phase 220 volt electric motor just measure one line. That already represents your line current. That line current is equal to your total current circulating in your motor.
Yes. The wattmeter's current coil will have to be connected into one of the line conductors, and its voltage coil between that same line conductor and the neutral point of the load. Connected this way, the wattmeter's voltage coil is measuring one of the three phase voltages (line-to-neutral voltage) while its current coil is measuring the corresponding phase current (for a 4-wire system, the phase current = line current). The power factor (cosine of the phase angle) is accounted for automatically within the wattmeter. So the wattmeter will measure the true power (in watts) of one phase. The total power, therefore, will be 3x the wattmeter reading -providing, of course, that the load is balanced (i.e. each phase is identical). WebRep currentVote noRating noWeight
Star (or wye) connection is where each of the three phases has a fourth conductor, neutral, as its current return. Current flow in this configuration is phase to neutral, which is also grounded back at the distribution center. There will be five total connections, phase A, B, and C, neutral, and (protective earth) ground. Delta connection is where each of the three phases uses the prior phase as its current return. Current flow in this configuration is phase to phase, and there is no neutral, though there is still a ground. There will be four total connections, phase A, B, and C, and (protective earth) ground.
In this case, to get the equivalent resistance, first you use the parallel formula (1/R = 1/R1 + 1/R2) to calculate the equivalent resistors in parallel. Then you calculate the series resistance of this combination, with the other resistor.
The voltage and current will give the kVA, but the kW depends on the power factor of whatever load is connected to the supply. For a (let's say) 11 kV supply, the voltage from line to neutral is 11,000/sqrt(3) which is 6351 v. The kVA on each phase is 6.351 times the current, and you just add up the three kVA values to find the total. At higher voltges like 11 kV the three currents in the lines are usually very nearly equal.
Add them upAnswerThere is no 'total' current in a three-phase system. The current flowing in each line (not 'phase') is considered separately. And you most definitely don't 'add them up'!
You will need to determine the power per phase, and add them up to give the total power of the three-phase load. To do this, you will need to multiply the phase-voltage by the phase current by the power factor -for each phase.
In a single phase 220 volt electric motor just measure one line. That already represents your line current. That line current is equal to your total current circulating in your motor.
There is no such thing as a 'total current' for a three-phase generator in the sense that you suggest -i.e. the sum of the phase currents. Current ratings are based the current that the machine can deliver to a load on a 'per line' basis.
For a balanced load, you don't have to worry about phase values when you want to determine the power (or, in this case, the energy), whether delta or wye. Rather, you always use line values:P = 1.732 VL IL cos (phase angle)For an unbalanced load, however, you need to measure the phase voltage and phase current and power factor for each of the three phases, and add them together:P = [VpIp cos (phase angle)]phase A +[VpIpcos (phase angle)]phase B+[VpIp cos (phase angle)]phase CTo then calculate the energy expended in kilowatt hours, you need to multiply the total power (as calculated above), expressed in kilowatts, by the time for which the load is operating, expressed in hours.
a: usually taking the high side of the buss or the return and measuring the current
Yes. The wattmeter's current coil will have to be connected into one of the line conductors, and its voltage coil between that same line conductor and the neutral point of the load. Connected this way, the wattmeter's voltage coil is measuring one of the three phase voltages (line-to-neutral voltage) while its current coil is measuring the corresponding phase current (for a 4-wire system, the phase current = line current). The power factor (cosine of the phase angle) is accounted for automatically within the wattmeter. So the wattmeter will measure the true power (in watts) of one phase. The total power, therefore, will be 3x the wattmeter reading -providing, of course, that the load is balanced (i.e. each phase is identical). WebRep currentVote noRating noWeight
By measuring the length and breadth of the pool we can measure its area.
copper losses are power losses due to flow of current in the wires or resistances,if the resistance is R, current is I then copper losses are I2R. for a 3-phase system; copper losses are same but for a single line, total losses are 3I2R.
Total KVA of the transformer divided by (square root of 3 times the voltage). This will give the individual phase currents. These individual phase currents will be 120 degrees out of phase with each other.
Star (or wye) connection is where each of the three phases has a fourth conductor, neutral, as its current return. Current flow in this configuration is phase to neutral, which is also grounded back at the distribution center. There will be five total connections, phase A, B, and C, neutral, and (protective earth) ground. Delta connection is where each of the three phases uses the prior phase as its current return. Current flow in this configuration is phase to phase, and there is no neutral, though there is still a ground. There will be four total connections, phase A, B, and C, and (protective earth) ground.
In this case, to get the equivalent resistance, first you use the parallel formula (1/R = 1/R1 + 1/R2) to calculate the equivalent resistors in parallel. Then you calculate the series resistance of this combination, with the other resistor.