The voltage and current will give the kVA, but the kW depends on the power factor of whatever load is connected to the supply.
For a (let's say) 11 kV supply, the voltage from line to neutral is 11,000/sqrt(3) which is 6351 v. The kVA on each phase is 6.351 times the current, and you just add up the three kVA values to find the total.
At higher voltges like 11 kV the three currents in the lines are usually very nearly equal.
You have to know the power loading and phase angle (or power factor) between each pairh of the phases, otherwise you could be making serious errors.
96 kW means 32 kW from each phase. If the load is star connected each resistor has 277 volts across it and carries 32,000/277 amps, 115.5 amps. The load resistors are 277/115.5 ohms or 2.40 ohms If the load is delta connected each resistor has 480 volts across it and carries 66.7 amps. The load resistors are 480/66.7 ohms or 7.20 ohms. In both cases the line current is 115.5 amps.
For practical purposes, transformers do not lose power during transformation. Thus, if you have the VA of the transformer, you can simply divide the VA by the voltage to get a rough idea of maximum current. In a real application, the maximum amperage will be dependent on the phase angle of the transformer.
You can't measure an RLA. It is determined by the factory that manufactured the compressor. To answer your other question, a 230 volt load is actually using both legs as part of the circuit, so you can measure either leg with a current meter but there is no need to add them up.
A 7.5 kW three phase load will be balanced by the manufacturer. When connected to a three phase source the line current on each phase will be equal.
Measuring the current in each phase (or do you mean 'line'?) will not give you sufficient information to work out what you are asking for.
It means 225 amps on each phase.
In a standard 3 phase system in North America, 7kVa would be equivalent to 19.5 amps on each phase. The equation is: 7kva*1000/208v/1.73=19.45 amps (3 phase)
Assuming it is a 208-volt line voltage (as normal in 3-phase) the phase voltage is that divided by sqrt(3), or 120 volts. Each phase has to supply 10 kW so the current on each phase is 83.3 amps.
For a single phase circuit, the equation you are looking for is I = W/E. Amps = Watts/Volts.
thong each wire using amp meter
You have to know the power loading and phase angle (or power factor) between each pairh of the phases, otherwise you could be making serious errors.
Yes. In a 3-phase motor, all 3 phases have the same current.
For a balanced load, you don't have to worry about phase values when you want to determine the power (or, in this case, the energy), whether delta or wye. Rather, you always use line values:P = 1.732 VL IL cos (phase angle)For an unbalanced load, however, you need to measure the phase voltage and phase current and power factor for each of the three phases, and add them together:P = [VpIp cos (phase angle)]phase A +[VpIpcos (phase angle)]phase B+[VpIp cos (phase angle)]phase CTo then calculate the energy expended in kilowatt hours, you need to multiply the total power (as calculated above), expressed in kilowatts, by the time for which the load is operating, expressed in hours.
To answer this question the voltage of the generator must be given.
Yes - a 3 phase load (in a balanced network) that consumes 270A would have a flow of 90A down each phase
You can't. Currents in three-phase systems are measured in each of the individual line conductors.