yes
Sodium does not have a full outer valence shell. It has one electron in its outermost shell, which makes it very reactive and likely to lose that electron to achieve stability.
Sodium is in the third group in the periodic table. It meens that sodium has three shell. First shell - 2 electrons, second shell - 8 electrons, third shell (outer energy level) - 1 electron.
The valence shell of sodium has one electron.
the valence shell is the outermost shell of an atom that has free electrons for taking part in chemical reactions... the valence shell of sodium has one free electron
there is only one electron in the outermost shell of Na.
The valence electron configuration of a sodium atom is 3s1, meaning it has one electron in the 3s orbital in the outermost shell. Sodium has one electron in its outermost shell, making it highly reactive.
There's only one. Because of this it is very easy for sodium to lose that one electron so that it can have a full electron shell like that of neon. Sodium's first shell has two electrons, and it's second shell has 8 electrons.
For group 1 elements : lithium , sodium, potassium...etc All of them have one valence electrons , however Rubidium(Rb) have two valence electrons. Therefore, Cesium have one valence electrons. :D
no protons, one electron as it is in group I of the periodic table
Sodium has one electron in its outermost principal energy level, also known as the valence shell.
As a neutral atom, sodium possesses 1 electron in its outermost (3rd) energy level. As a 1+ ion, it possesses 8 electrons in its second energy level, forming an octet, which is the optimum number of electrons for sodium to possess in its outermost energy shell.
Sodium has one electron in its outer ring.