No. It's what we see.
(The amount it actually gives off is called the absolute magnitude.)
No, the light it really gives off is called the absolute magnitude.
It is actually absolute magnitude, opposed to apparent magnitude which is how much light stars appear to give off.
That apparent course is actually more to do with the fact that the shuttle and most satellites orbit the earth at angles to both the lines of latitude and longitude. Also there is the factor that Earth is rotating as they orbit. It is a combination of the two, shown on a two-dimensional screen that gives the apparent serpentine orbit, although that is not what is actually happening.
it is florecent gasses that take thousands of years for the light to travel to earth so by the time we see the stars, they could already be long gone
Electromagnetic radiation
A star.
It is actually absolute magnitude, opposed to apparent magnitude which is how much light stars appear to give off.
The apparent magnitude of a star is a measure of its brightness as seen from Earth, the lower the number, the brighter a star is. Ex. a star that has an apparent magnitude of -20 is WAY brighter from Earth than a star with a apparent magnitude of 20.
The amount of light a star gives off is the intensity or luminosity. Absolute Magnitude measures the amount of light given off.
It is actually absolute magnitude, opposed to apparent magnitude which is how much light stars appear to give off.
its called magnitude or luminosity. :) hope it helped you.
It's electromagnetic radiation, part of the spectrum of which is visible light. The question actually asks what is the AMOUNT of light a star gives off. So we are looking for a quantity here, measured in photons. In relative terms we use absolute and absolute magnitude. [See related question]
It's electromagnetic radiation, part of the spectrum of which is visible light. The question actually asks what is the AMOUNT of light a star gives off. So we are looking for a quantity here, measured in photons. In relative terms we use absolute and absolute magnitude. [See related question]
The basic idea is:* Measure the star's apparent magnitude * Calculate the star's distance * The absolute magnitude can be directly calculated from these two pieces of information. However, adjustments may need to be made for extinction - that is, if there is a lot of dust or gas between the star and us, it looks dimmer than without the dust or gas. Without extinction, the Wikipedia gives the following formula: M = m - 5((log10 DL) - 1) Where M is the absolute magnitude, m is the apparent magnitude, DL is the distance in parsec.
The amount of light, or brightness, of a star is measured by it magnitude - the lower the magnitude the brighter the object. The following gives an idea of the range when measured in visible light: The sun (as viewed from Earth) is at a magnitude of -26.73The darkest object visible to the naked eye (under very dark conditions) is at around magnitude 7.7The faintest visible object that can be seen by the Hubble Space Telescope is around magnitude 31.
absolute bolometric magnitude
Scalar and vector quantities give magnitude, and that makes them similar. The difference is that the vector quantity gives direction as well as magnitude. plz check out this for further details vHMnGsOrU5A
That apparent course is actually more to do with the fact that the shuttle and most satellites orbit the earth at angles to both the lines of latitude and longitude. Also there is the factor that Earth is rotating as they orbit. It is a combination of the two, shown on a two-dimensional screen that gives the apparent serpentine orbit, although that is not what is actually happening.