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The reaction that occurs between a strong monoprotic acid and sodium hydroxide is H++OH- => H2O. This reaction is the same for all strong monoprotic acids and sodium hydroxide so, in theory, they should all have the same standard enthalpy of reaction. In practice, there are very slight differences between acids. If you are in a freshman or sophmore chemistry class, say yes. If you are in physical or analytical chemistry say no.

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Q: Is the enthalpy change of the chemical reaction between a monoprotic acid and sodium hydroxide the same for all strong monoprotic acids?
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What does the enthaply of reaction measure?

The enthalpy of reaction is the change of the system enthalpy after a chemical reaction.


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The enthalpy of a chemical reaction is the change of heat during this reaction.


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Would the enthalpy change be different if solid sodium hydroxide pellets were added to hydrochloric acid instead of adding hydrochloric acid to sodium hydroxide solution?

Yes, the reaction involving the solid is actually an individual step in the equation of the reaction between the solutions. If you were to add the change in enthalpy of the reaction with the solid NaOh to the change in enthalpy of the other step in the reaction (that's adding water and the NaOh pellets) you would find the sum equivalent to the change in enthalpy of the reaction involving the two solutions (this is supported by Hess's law). I suggest that you consider Hess's law for more information.


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