yes
to fcking
Maintain proper air pressure in tires.
Air pressure checks on car tires is a very quick and easy process that is usually done at no charge at any gas station or service station. It literally takes 10 seconds to check the air pressure in your tires and any good auto repair shop will gladly do it for you at no charge.
In the context of thermodynamics, work done on a gas can be calculated using the formula W = PΔV, where P is pressure and ΔV is the change in volume. Since work done is measured in joules, pressure multiplied by volume change gives the work done in joules.
The process of mounting and balancing a set of tires is done with the tires off the vehicle but it is generally understood that the tires will be fitted to the vehicle after the work of mounting and balancing is done .
Need to know what type of pressure check, engine compression, cooling system, ac system, air pressure in tires, etc. Then we need to know the year, make, model and engine info.
Tire maintenance is best done when cold it is the closest to the actual pressure as air warms the pressure rises it may be as much as 10 pounds difference in cars so..... filling a tire warm will result in lower than safe operation pressure when cold.
Though trailer tires should be replaced after 3 years at least, regular maintenance will extend the life of them. Correct tire inflation pressure, not overloading the vehicle, inspecting the tires regularly, and observing good driving habits go along with this process.
The work done by the gas during the expansion is equal to the area under the pressure-volume curve on a graph of the process.
In an adiabatic process, no heat is exchanged with the surroundings. The work done is the change in internal energy of the system, which is equal to the pressure times the change in volume.
they are not quality tires. the vulcanizing process is not done properly. tire thread separation is a common occurrence.
The amount of work done is equal to the force applied multiplied by the distance the object is raised. In this case, the work done is equal to the force F multiplied by the height of 5 meters.