Ray Padula makes a garden sprinkler that sits on a tripod. It will cover up to 90 feet. It has an adjustable sprayer for part circles if you do not want to cover the entire area with water. The garden sprinkler also has a lifetime warranty! Garden Harvest Supply is a good source for Ray Padual garden sprinklers.
60*12 = 720 miles
Depends on the available pressure If you have 60 PSI coming into a structure then you will get 60 PSI out of the sprinkler Just look at the "K" factoring for friction losses
60
The LCM of 12 and 60 is 60. The GCF of 12 and 60 is 12.
A = lw 60 = l * 50 l = 60 / 50 l = 6/5 m
1/12 × 60 = 60/12 = 60 ÷ 12 = 5
12% of 60% as a percent = 100*12/100*60/100 = 7.2%12% of 60% as a percent = 100*12/100*60/100 = 7.2%12% of 60% as a percent = 100*12/100*60/100 = 7.2%12% of 60% as a percent = 100*12/100*60/100 = 7.2%
60 + 12 = 72
12% of 60 = 60 * 12/100 = 7.2
12 times 5 is 60
The force at the input of a sprinkler can be found from F = PA; where P is the pressure of the water at the spigot or source of the water to the sprinkler and A is the x-sectional area of the input hose to the sprinkler. EX: A typical house-hold water pressure is about P = 60 psi in the US. And a typical hose is a 1/2 inch diameter; so A = pi (D/2)^2 = pi (.5/2)^2 in^2 is the x-sectional area. Which means the force at the input would be F = PA = 60pi()(.5/2)^2 = 11.78097245 ~ 12 pounds of input force. ANS.
The HCF of 12 and 60 is 12