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Whereabouts in Australia are you, as i need to buy some tin/antimony to melt down for casting purposes.

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9y ago
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Q: Is there a market for scrap pewter in Australia I have a large quantity which is 97 percent tin and a small amount of antimony apparently.?
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What is the definition and example of percent proportion?

compares part of a quantity to the hole quantity using a percent


What is the empirical formula of a compound that is 50.7 percent antimony and 49.3 percent selenium by weight?

We assume 100 grams of the compound and turn those percentages into grams and get the moles. 50.7 grams antimony (1 mole Sb/121.8 gram) = 0.41626 moles antimony ================================ Now, the smallest mole number (antimony) becomes 1 and the other number is divided by it(antimony) to get the empirical numbers. 0.62467 moles Se/0.41626 moles Sb = 1.5 ----------------so, this happens sometimes and this is what we do (SbSe1.5)*2 = Sb2Se3 -----------------The empirical formula Antimony selenide


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The atomic mass of an element is the weighted average of the masses of its isotopes. You know that: Antimony-121 has a mass of 120.9038 u, x% abundance Antimony-123 has a mass of 122.9042 u, y% abundance There are only 2 isotopes for antimony and their percent abundances should add up to 100%. In other words: x% + y% = 100% y = 1-x (percentages written as decimals) So, now let's put everything together. In order to calculate the atomic mass, multiply the percent abundance of an isotope by its atomic mass; then add the product of all the isotopes: (Atomic Mass of Antimony-121)(Percent Abundance of Antimony-121) + (Atomic Mass of Antimony-123)(Percent Abundance of Antimony-123) = Atomic Mass of Element Antimony (120.9038 amu)(x) + (122.9042 amu)(y) = 121.760 amu Replacing 1-x for y gives: (120.9038 amu)(x) + (122.9042 amu)(1-x) = 121.760 amu Solve for x: 120.9038x + 122.9042 -122.9042x = 121.760 amu -2.0040x = -1.1442 x = 0.57096 = 57.096% Solve for y: y = 1 - x y = 1 - 0.57096 = 0.42904 = 42.904%


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