Any reaction occur.
When copper chloride is mixed with sodium hydroxide, a precipitation reaction occurs where solid copper(II) hydroxide is formed. The balanced chemical equation for this reaction is: CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl. This reaction is a double displacement reaction where copper ions and hydroxide ions switch partners to form the solid copper hydroxide.
The reaction between sodium hypochlorite and copper results in the formation of copper(II) oxide and sodium chloride. This is an oxidation-reduction reaction where the sodium hypochlorite oxidizes the copper metal to form copper oxide and is itself reduced to sodium chloride.
When sodium sulfite solution is added to copper chloride solution, a white precipitate of copper sulfite forms. This precipitation reaction occurs because sodium sulfite reacts with copper chloride to form insoluble copper sulfite.
When sodium chloride reacts with copper sulfate, sodium sulfate and copper chloride are formed. This is a double displacement reaction where the cations and anions of the two compounds switch partners.
When sodium sesquicarbonate (Na₂CO₃·NaHCO₃·2H₂O) reacts with copper(II) chloride (CuCl₂), a double displacement reaction occurs, resulting in the formation of copper(II) carbonate (CuCO₃) and sodium chloride (NaCl). The copper(II) carbonate precipitates out of solution, typically appearing as a blue-green solid. Additionally, sodium chloride remains dissolved in the solution. The overall reaction highlights the formation of an insoluble compound from soluble reactants.
They will react to form aqueous sodium chloride and solid copper carbonate in a double replacement reaction, also known as a double displacement reaction. CuCl2(aq) + Na2CO3(aq) --> CuCO3(s) + 2NaCl(aq)
Assuming they are dissolved in water the mixture turns green. Presumably the copper and chloride associate and the sodium and sulphate remains clear. The cystalised substance remains green although the colour deepens when it is dry.
Any reaction occur.
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
Sodium chloride is a salt and copper is an element.
There is no equation because there is no reaction.
You would write the balanced chemical equation as: CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl. This reaction involves the double displacement of ions between copper (II) chloride and sodium hydroxide to form copper (II) hydroxide and sodium chloride.