You need a graphic concentration versus absorbance.
the experimental rate law of a simple reaction A->B+C is v=k[A].calculate the change in the reaction rate when:(a) the concentration of A is tripled (b) the concen-tration of A is halved
We would need to know the path length and the molar extinction coefficient to answer that question. If you know these, it's an extremely simple matter of Beer's Law and algebra.
The equation for fermentation of the simple sugars to alcohol are, Sugar (glucose) yields alcohol (Ethyl alcohol) + CO2 (g) + energy.
The movement of molecules from an area of high concentration of that molecule to an area of lower concentration is called simple diffusion.
Simple diffusion
I'm doing this lab, and it was explained to me by my instructor... Basically, on the x-axis you'll have the concentration of a substance, and on the y-axis you'll have the %T, or A, the absorbance of the substance when it's put into a spectrophotometer. so you plot the points, get a line of best fit (this is your calibration curve), and then basically you use that line to get the concentration of the substance, when you've already calculated the A. . And from that concentration, you can extrapolate the concentration of the reactants/products (Depending on what you're looking for) to find the equilibrium constant. Here's an example: iron and thiocyanate ions bond to form iron thiocyanate in the following equation: Fe(3+) + SCN(-) --> FeNCS(2+) For the experiment I did, a calibration curve was made with reacted Fe(3+) and SCN(-). So for my calibration curve, I got the concentration of FeNCS(2+) on the x-axis, and the absorbance or A on the y-axis. So you basically got to find the equilibrium concentrations of the Fe(3+) and the SCN(-), cuz you've already got the equilibrium concentration for FeNCS(2+). So you start with the initial, use the equilibrium FeNCS(2+) to calculate the equilibrium concentration of the reactants. Here's the equation: equilibrium [Fe(3+)] = initial [Fe(3+)] - equilibrium [FeNCS(2+)]. And the same goes for the SCN ion.. you just switch out the numbers. So now that you got all that, it's simply a matter of dividing the product concentrations by the multiplication of the reactant concentrations. and boom, you have found the equilibrium constant. Keep it simple stupid, y'all. There is another way to find it, and that's using the Beer-Lambert's law..
the experimental rate law of a simple reaction A->B+C is v=k[A].calculate the change in the reaction rate when:(a) the concentration of A is tripled (b) the concen-tration of A is halved
Simple equation: ECD, ppg = [ (annular pressure, loss, psi ) ÷ (0.052 x TVD, ft) ] + (mud weight, in use, ppg)
you find the hard equation and simplify it....
Simple form is where all of the variables in the equation are put on one side on the equation, which a zero on opposite side of the equation ex. a+b+c=0 18a + 4b + 5 = 0
Yes, simple diffusion/passive diffusion is the movement of a particle from an area of high concentration to one of lower concentration.
What disadvantages are there to using parametric equations for numeric values?
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diffusion
It is in simple terms:
simplify. Can you simplify this equation?
For all dilution/ concentration problems you use the simple equation: M1V1 = M2V2 2.40*V2 = 8.25*25 V2 = (8.25*25)/2.40 V2 = 85.9mL Final volume will be 86mL.