Yes. Once dielectric breakdown occurs the circuit is now completed through a conductive breakdown channel in the dielectric. The current injected in one end of the dielectric is matched by the current coming out of the other end.
A: THAT IS CORRECT a diode conducts only one way that is why it is called a semiconductor Reversing the voltage no current will flow until breakdown.
Capacitors resist a change in voltage. It takes current to effect a voltage change, resulting in the current "leading" the voltage. Similarly, inductors resist a change in current. It takes voltage to effect a current change, resulting in the current "lagging" the voltage.
If the zener diode is in zener breakdown the voltage across the zener diode remains constant regardless of current (for the ideal zener diode). Real zener diodes have parasitic resistance that causes the voltage across the zener diode to increase slightly with increased current, but due to temperature dependant variations in this parasitic resistance as well as temperature dependant variations in the zener breakdown voltage, this change in voltage in real zener diodes cannot be described by a simple linear factor.
Drain-to-source breakdown voltage (BVdss) should not change appreciably until the gate-to-source voltage (Vgs) approaches the device's threshold voltage (Vth). In that case, the drain to source voltage becomes the product of the drain-to-source current (Ids) and the device's on-state resistance (Rds-on) at the given Vgs.
Capacitors charge by transferring charge from one plate to the other. This is not the same as a battery, though it can seem so. They oppose a change in voltage because the two plates are close to each other, separated by the dielectric, and the transfer of charge requires current. Once charged, however, the current becomes zero. The differential equation describing a capacitor is dv/dt = i/c, or volts per second = current over capacitance.
If current increases, then voltage also has to increase, assuming that resistance stay relatively the same. Power will also increase. Since power is the product of voltage and current, then the power increase would be the square of the voltage or current change.
in ac circuits power,P=VICOS@ @ is the angle between voltage and current. in dc P=VI V is the voltage I is the current. Power (in Watts) is current (A) x voltage (V)
Voltage and current are two different things. Voltage is potential energy per charge, in joules per coulomb, while current is charge transfer rate, in coulombs per second. Its that same as saying that a battery has voltage but no current, because there is no load. Well, a capacitor resists a change in voltage by requiring a current to change the voltage. Once that voltage is achieved, there is infinite resistance to the voltage, and thus no current.
A change in current causes a voltage to be induced into an inductive circuit, which opposes that change of current. This is because the change in current is accompanied by a change in magnetic flux which 'cuts' the conductors and induces a voltage into them.
Voltage is equal to the Current multiplied by the Resistance.Without changing the resistance, increasing the applied voltage in a circuit will increase current flow. There is a simple, direct relationship between voltage and current. Double the voltage, twice the current will flow. Triple the voltage, and the current will triple. As voltage (E) equals current (I) times resistance (R), when resistance is fixed, what happens to voltage will happen to current.
Ohm's Law: V = I*R, so Voltage and Current are directly proportional and a change in voltage will result in a proportional change in current. (The current reduces by the same factor)
Change the resistance in the circuit