Ohm's Law: V = I*R, so Voltage and Current are directly proportional and a change in voltage will result in a proportional change in current. (The current reduces by the same factor)
Based on the simplest Electrical Equation V = I * R,(reads: voltage equals current multiplied by resistance)then, rearranged I = V / R .As resistance decreases, current flow proportionately increases
Because by increasing the load resistance, the total circuit resistance is reduced. This means with less resistance, there is more current drawn from the source. Doubling the size of a load resistor increases the load current.
The answer depends entirely upon the scenario. Are you dealing with AC or DC? Does your circuit contain passive components or both passive and active components?For example, if you a simply dealing with a resistive DC circuit, you can derive your answer from Ohm's law, V = IR. Rearranging for current, I = V/R, so if you double the voltage, the current is subsequently doubled.
Voltage = resistance X current abbreviated,V = C * RIf you halve the voltage of the current, then the other side of the equation must also be halved; therefore, you get:(1/2)V=(1/2)(C*R)which is the same as:(1/2)V=(1/2)(C)(R)which means that either the current or the resistance must be halved as well, and because the resistance stays the same, then the current is halved.
When voltage and current waveforms are out of synch the power factor is reduced. In a pure resistance load the PF is 1. When inductance and capacitance is involved the PF is from 0 to 1.
As the resistance is reduced across the same voltage, the current increases.
Based on the simplest Electrical Equation V = I * R,(reads: voltage equals current multiplied by resistance)then, rearranged I = V / R .As resistance decreases, current flow proportionately increases
Using Ohms Law: V = I x R, where V (Voltage), I (Current), and R (Resistance). re-arranging: V/R = I Therefore if you double both the Voltage and the Resistance, the current remains unchanged.Current = Voltage / Resistance. If both resistance and voltage double the current remains the same.
Ohms law is V=I X R. If resistance (R) is reduced and current (I) is constant, then voltage (V) must decrease. You can see from the equation that they are proportional to one another. If, however, R is reduced and V is held constant, then I must increase (I and R are inversely proportional). The only way V can increase is if either or both I and R increase.
current will increase
The resistance is increased, the voltage across each bulb is decreased and the current through the circuit is reduced.
increase
If voltage increases and the resistance stays the same the current must increase. According to Ohm's LawV~I (Directly Proportional) and V=RI where R is the constant of Proportionality, Resistance.
I = V / R I = V / (0.65 R) I = 1.54 V / R Current increases by about 54%
the power will be reduced to the haflf because P=V2/R so when the resistance doubles the power reduced to the half of itsoriginal value
For the individual resistor, the current is constant, regardless of any other resister that's attached to it in parallel. The current that results from all the resistors combined decreases as the resistance of one or more of the resistors increases.
Because by increasing the load resistance, the total circuit resistance is reduced. This means with less resistance, there is more current drawn from the source. Doubling the size of a load resistor increases the load current.