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Voltage = resistance X current abbreviated,
V = C * R


If you halve the voltage of the current, then the other side of the equation must also be halved; therefore, you get:


(1/2)V=(1/2)(C*R)


which is the same as:


(1/2)V=(1/2)(C)(R)


which means that either the current or the resistance must be halved as well, and because the resistance stays the same, then the current is halved.

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14y ago
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12y ago

It will be half its original value I= V/R

the power dissipated by the circuit will be reduced to a quarter of its original value.

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Q: How will a current change if the resistance of a circuit remain constant while the voltage across the circuit decreases to half its original value?
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