HF
No, there is no such compound
Fluorine always has a negative oxidation number when it appears in any binary compound because it is the most electronegative element on the periodic table. This means it attracts electrons strongly towards itself, leading to a negative oxidation state in chemical compounds.
no, it does not exist
The oxidation state of iodine in the compound in the question is -1, as it is in any compound with a name that properly includes the word "iodide" instead of "iodine". "Iodide" is the name of the anion with formula I-1.
The element which has the same oxidation number in all of its known compounds is fluorine. Fluorine always has an oxidation number of -1 in its compounds because it is the most electronegative element.
The oxidation number of fluorine is -1. Fluorine is one of the most electronegative elements and tends to gain an electron to achieve a full outer shell, resulting in an oxidation number of -1 in most compounds.
Fluorine is the only halogen that does not naturally exist in any positive oxidation state. The other halogens - chlorine, bromine, iodine, and astatine - can exist in various positive oxidation states, though they are less common in nature compared to their negative oxidation states.
The sum of all oxidation numbers in any compound is zero. This is because atoms in a compound are electrically neutral, and the oxidation numbers reflect the charge of the atoms when they gain or lose electrons.
The oxidation state (or number) is zero. This is true for any element in any of its allotropic elemental forms.
The name gives the clue. If any chemical is described as '-ous' it has the lower oxidation state. If described as '-ic' , it has the higher oxidation state, Hence Ferrous chloride is 'Iron(II) chloride' ( FeCl2) Ferric chloride is 'Iron(III) chloride' ( FeCl3). Similarly with Nitric Acid and Nitrous Acid ( HNO3/HNO2) Sulphuric acid and Sulphurous Acid (H2SO4/H2SO3)
This formula is K2PtF6. The six fluorine atoms are indicated by the prefix "hexa"; each fluorine atom always has -1 as its oxidation state in a compound with any other element; the oxidation number of platinum is specified by "IV" and is positive; this means that two additional positive oxidation numbers are required from the remaining element, potassium, which in compounds always has an oxidation number of +1 per atom, so that two atoms are required. The order of the atomic symbols follows from the rule that the least electronegative element's symbol should be written first and the most electronegative element's symbol should be last.
As with any element, the oxidation state of oxygen is 0 in its elemental form.