As long as any part of the object ... doesn't matter how much ... is below the surface
of the water ... doesn't matter how far ... there is buoyant force on it.
The whole east coastline is ocean; from top to bottom.
yes at the bottom of the ocean.
they went to the bottom of the ocean and poseidon gave them turkey
The US battleship Pennsylvania is resting on the bottom of the Pacific Ocean. Her sister, the USS Arizona is resting on the bottom of Pearl harbor. The oldest US battleship still afloat is the USS Texas. Her sister, the USS New York is also resting on the bottom of the Pacific Ocean. The only pre-dreadnaught remaining in the world, is the IJN Mikasa; which is preserved in Japan as a memorial.
The Titanic hit an iceberg on April 14 1912, around midnight. The Titanic broke in half and sank to the bottom of the Atlantic Ocean April 15, 2:20 A.M.1912
As long as any part of the object ... doesn't matter how much ... is below the surface of the water ... doesn't matter how far ... there is buoyant force on it.
Everything has weight, but when something is submerged in water, it experiences a buoyant force that counteracts weight. If this buoyant force is stronger than an object's weight, the object floats (conversely, if it is weaker, it sinks).To calculate weight, multiply the mass of an object (in kilograms) by g, Earth's gravitational field at its surface (approximately 9.81 m/s/s).To calculate buoyant force, multiply the density of the fluid in which the object is submersed (for water, this is approximately 1000 kg/m^3) by the volume of the object submersed (meaning ONLY the volume of the part that actually displaces fluid) by g.Both results will carry the SI unit of force "Newtons."
An iceberg floating in the ocean is affected by the water pressure and buoyant force on the basis of the Archimedes' principle. This dictates that a volume of a liquid must supported by the pressure of a surrounding liquid.Ê
A large cruise ship.
The force is the same as long as the volume submersed is the same
yes, it is the equivalent to the weight of the water displaced by the solid material of the boat.
Increasing the salinity of fresh water makes the water denser. The denser the water the less deeply an object will sink into the water. The very saltiness of the Dead Sea, means that people can float on the surface without effort. A ship, after displacing its weight, will float higher on the ocean, than it would if sailing on fresh water.
I suspect you mean the gravitational acceleration constant which is about 9.81 m/s^2. This value is actually only valid at Earth's surface (and it also varies from place to place). So in general the answer to your question is no. It might, but it won't be in general. The value is calculated by using Newton's Law of gravitation: F = G m1*m2 / r^2. Where F is the gravitational force, m1 is the mass of the Earth and m2 is the mass of an object. r is the distance from the object to the center of the Earth. Because r does not differ much, G is just a constant (called Newton's Gravitational Constant), and m1 also does not change much, we usually do the following: If we are interested in the acceleration an object experiences due to gravity we can use Newton's Second Law: F = m * a. If we take m as the mass of our object, and a its acceleration due to the gravitational force we must have: G m1 * m / r^2 = m * a If we cross out the m (or m2) on both sides we end up with: a = G m1 / r^2 This a is usually called g. It does not vary much in everyday life, but it does ultimately, so g varies with height.
Not only from the ocean. EVERY object in the Universe attracts EVERY OTHER OBJECT, through a force called gravity. So, the ocean attracts us, but so does every other part of planet Earth.
The buoyancy of an object submerged in water does not normally change substantially with depth, but there are caveats to this answer. The buoyant force is equal to the weight of fluid displaced. In the case of non-compressible liquids the buoyancy force does not change with depth. No material is truly incompressible, so if you go really deep (the bottom of the ocean for example), the fluid is compressed a little bit, and so a given volume of the fluid is heavier (denser) and the buoyancy force is greater. (The difference in the density of sea water between the surface and the greatest depth of the ocean is only a few percent.) Buoyancy forces are also present in compressible gases, for example, a balloon in Earth's atmosphere. In this case, air closer to the Earth's surface is more compressed and thus significantly denser, meaning a fixed volume object will experience a noticeably greater buoyancy force at lower altitudes. Finally, the buoyant force can change with depth because the volume of the object changes with depth. Certainly this is an important factor with balloons in air and if you submerged a balloon in water the effect of pressure on the volume of the balloon would be a dominant factor on buoyancy. This is present, though small, for solid objects as well. One more thing, if you are being really picky, gravity changes with depth as well and so affects buoyancy. Obviously not important on Earth, but dropping a mass into a gas planet does have to incorporate the change of gravity with depth and all the other caveats mentioned above.
If the ability to float did not exist many things that depend on flotation to work would not. If ice didn't float, we would all die. For more details on the last sentence, I'm sure your science teacher will know.
First of all, pressure is defined as force per unit area. In the case of a lake, the main force acting upon an object in the lake would be gravity, among others. At the surface of the lake, the pressure on the object would be the force that the column of air above exerts on it, divided by the area that the force is acting upon. On the other hand, the pressure on the object at the bottom of a lake would be the force of the column of air PLUS the force of the lake water above, divided by the area that the force is acting upon. Therefore, the pressure must be greater at the bottom of the lake.