No, the use of 'namespace std' is not compulsory. You can specifiy it on any object reference. Specifying 'namespace' simply provides a default value.
Contrast ...
using namespace std;
cout << "Hello world!" << endl;
... with ...
std::cout << "Hello world!" << std::endl;
You don't "have to" use "using namespace std;" in C++. It just makes typing easier. Here are two identical programs, one with, and one without.
#include
using namespace std;
int main () {
cout << "Hello C++ World!" << endl;
return 0;
}
#include
int main () {
std::cout << "Hello C++ World!" << std::endl;
return 0;
}
The using namespace std statement identifies the default namespace when it is not explicitly stated in the code. If you did not specify a namespace, simple things like cout and endl would have to be specified as std::cout and std:endl.
No. You can't use namespace std even if you include stdio.h. At the very least you must include stddef.h before you can use namespace std.
#include <iostream> using namespace std;
A namespace is similar to a class in object oriented programming. A namespace contains functions defined by the programmer. for example namespace std contains functions like cout and cin.namespaces can be globaly declared like so: "using namespace std;"which includes all the functions located in the namespace std.if you only need to use cout you can globaly declare only cout like this "using std::cout;"orstd::cout
The std namespace is the standard library, which includes many of the common data types, constants, structures, classes and functions that you will use to create C++ programs. There are very few non-trivial C++ programs that do no make use of at least some portion of the standard library at some point. Note that you need only include those portions you actually use; there is no need to include the entire standard library. Any built-in functions that require the standard library will include only as much as they need to, whether you yourself include those portions or not.
#include <iostream> using namespace std; int main() { for(int i = 0; i <= 100; i++) { if(i % 2 != 0) { cout << i << endl; } } char wait; cin >> wait; return 0; }
No. You can't use namespace std even if you include stdio.h. At the very least you must include stddef.h before you can use namespace std.
#include <iostream> using namespace std;
A namespace is similar to a class in object oriented programming. A namespace contains functions defined by the programmer. for example namespace std contains functions like cout and cin.namespaces can be globaly declared like so: "using namespace std;"which includes all the functions located in the namespace std.if you only need to use cout you can globaly declare only cout like this "using std::cout;"orstd::cout
A quick and simple way to do this would be to add 'std::' directly in front of the data type that requires it. For example: a vector data type, without the line of code 'using namespace std' would look like this: 'std::vector' (without the inverted commas).
greatest = std::max (a, std::max(b, c));
#include<iostream> int main() { using namespace std; cout<<"Hello world!"<<endl; return( 0 ); }
#include<iostream> int main() { using namespace std; cout<<"Hello world!"<<endl; return(0); }
Use setprecision.Example:#include #include using namespace std; int main() { double f = 3.14159; cout
Download Dev-C++. Just google it. Hello World: #include <iostream> using namespace std; int main() { cout << "Hello World" << endl; }
If you do not include the directive using namespace stdin your program, any references to objects in namespace std will need be be qualified with that namespace. For instance...cout
#include <iostream> using standard namespace std; int main() { cout << "your prob shouldn't be taking c++"; return 0; }
#include<iostream> int main() { using namespace std; char c='A'; do { cout<<c; }while(c++<'Z'); cout<<endl; }