No.
C does not support operator overloading. If you mean C++ operator overloading, it depends on exactly what you wanted to do. If you wanted to '+' to strings, then you could write: string operator+(string a, string b) { // do something }
The plus operator between string constants allows string concatination: string a = "Hello, "; string b = "World!"; string c = a + b; The output of c would be: "Hello, World!".
Yes, a string can contain operator symbols, eg: const char *s= "+*-/";
String class is useful to accept inputs from commands prompt as string arguments
Any character can be used in string, except for \\0. char example [] = "A&B|C";
select *from emp
A string is, by definition, a character array. No conversion is required.
I guess by 'string' you mean a character-array; so the answer is: an array in itself is a pointer to its first element: arr==&arr[0]. (Note: it is a pointer-constantant, not a pointer-variable, so you cannot change it's value: 'arr= something' is wrong.)
A string is, by definition, a character array. No conversion is required.
Java does not support object overriding. It does support operator overloading by means of the "+" symbol which is used for both numeric addition as well as string concatenation.
Java doesn't always accept any input as a string it only do that when the input is entered from the " JOptionPane.InputDialog" but it can accept any other data type like integer or short from the console though Scanner class .
The instanceof keyword is used to determine if an object is of a particular class type.Example:Object obj = new String();if(obj instanceof String) {System.out.println("obj is a String!");}