AgBr precipitates and in light decomposes to bromine and silver metal.
potassium bromide + fluorine --> potassium fluoride + bromide
copper bromide + sodium Hydroxide = Copper Hydroxide + Sodium Bromide CuBr2 + 2NaOH = Cu (OH)2 + 2NaBr
ethyl magnesium bromide to propanol
It produces Bromomethane and Hydrogen Bromide Equation: CH4 + Br2 ----> CH3Br + HBr
CH4 + Br2 --> CH3Br + HBr
potassium bromide + fluorine --> potassium fluoride + bromide
When hydrogen bromide reacts with water, it forms hydrobromic acid, which can be represented by the chemical equation HBr + H2O → H3O+ + Br-. This reaction involves the dissociation of hydrogen bromide into H+ and Br- ions in solution.
copper bromide + sodium Hydroxide = Copper Hydroxide + Sodium Bromide CuBr2 + 2NaOH = Cu (OH)2 + 2NaBr
Magnesium bromide is a salt, not a base. It is formed by the reaction between magnesium oxide (a base) and hydrobromic acid to produce magnesium bromide and water.
The compound made in the reaction between bromine and potassium is potassium bromide (KBr). Bromine reacts with potassium to form a white crystalline solid compound.
This equation is:AgNO3 + KBr = AgBr(s) + KNO3Silver bromide is a white precipitate.
The reaction between NaOH (sodium hydroxide) and KBr (potassium bromide) would result in the formation of NaBr (sodium bromide) and KOH (potassium hydroxide) as products. This is a double displacement reaction where the cations and anions switch partners.
ethyl magnesium bromide to propanol
The products of the reaction between potassium bromide and chlorine are potassium chloride and bromine gas. The balanced chemical equation for this reaction is: 2KBr + Cl2 → 2KCl + Br2.
The products of the reaction between hydrogen bromide (HBr) and sodium hydroxide (NaOH) are sodium bromide (NaBr) and water (H2O). This is a neutralization reaction where the acid (HBr) reacts with the base (NaOH) to form a salt (NaBr) and water.
The products of the double replacement reaction between hydrogen bromide (HBr) and sodium hydroxide (NaOH) would be sodium bromide (NaBr) and water (H2O).
Ethyl bromide can be converted into butane through a series of steps involving elimination reactions. The ethyl bromide can be treated with a strong base, such as sodium ethoxide, to form ethylene gas. Ethylene gas can then be subjected to a hydrogenation reaction to produce butane.