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MWhere can I obtain repair parts for Fireplace insert ventless model no. UF-AUF-HC-29C artin Industries Inc?
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∙ 12y ago
I am looking for these parts also. Was wondering if you found them.
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∙ 12y ago
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How can the speed of light be written?
E = mc2c2 = E/mc = √E/mWhere E = energym = massc = speed of light186,000 miles per second (MPS), or 300,000 kilometers per second (KPS)
How many moles are in 0.50 of H2SO4?
Did you mean 0.5 g? or mg? or ml?Anyway, amount of substance in moles is calculated as m/Mwhere m is mass and M is molal mass.M (H2SO4) is 1*2 + 32 + 16*4 = 98 g/mole
What is the molar mass in grams of mole of an element equal to?
weight...'
What happens if an unbalanced force applied to an object doubles?
The acceleration, from the Newton's law, can be calculated as:a0 = F0/mwhere F0 is the unbalanced force, m is the mass of the object.This is a linear equation, so if you double the force by 2, the acceleration will double as well:a1 = 2F0/m = 2(F0/m) = 2a0
How unbalanced forces change the motion of objects?
The forces are vectors, meaning, they have a direction and an intensity. When multiple forces "attack" and object and the result force is not a zero, that means there is a resultant single force that affect the object. That single force has a direction and intensity. As a result of this, the object will start moving along the direction of the resultant force, accelerating with an acceleration that can be calculated as:a = F/mwhere:"a" is the acceleration in m/s2"F" is the intensity of the force"m" is the mass of the object.Now, if in the system of reference (read: from the observer's point of view) the object was moving linearly and with a constant speed, or it was not moving at all, the final direction of the movement can be calculated as a superimposition of the vectors of the initial movement and the changing vector of the accelerated movement caused by the resultant force mentioned above.
How would the acceleration of a car change if a truck motor replaced the usual motor.Consider the change in force and mass?
I assume the question means to say that a truck motor is more powerful than a car motor.Considering the equation a=F/mwhere a is acceleration, F is force and mis mass.Since the truck motor is more powerful than the usual motor, it provides a greater force to propel the car.So the driving force on the vehicle is greater.Since the car is smaller than the truck, its mass is less (assuming it's not denser for some reason).So the mass of the vehicle is lesser.Looking at the formula a=F/m:1. Increasing F makes a greater2. Decreasing m makes a greater(Try out random numbers if you want to see why.)So overall the effect is to make a greater.Therefore the acceleration of the car would increase.
How circulation of money is develop?
Quantity Theory of Money (1885)Developed by the Americans SIMON NEWCOMB (1835-1909) and Irving Fisher (1867-1947), the latter of whom's original equation stated in simple terms that the amount of money in circulation equals money national income; that is,MV = PTwhere M is money stock, V is velocity of circulation, P is average price level and T the number of transactions. The equation assumes that the velocity of circulation of money is stable (at least in the short term) and that transactions are fixed by consumer tastes and the behavior of firms.Quantity theory of money was superseded by Keynesian analysis. Members of the Cambridge School were concerned with the volume of money held given the number of transactions carried out. They argued that the greater the number of transactions, the greater the amount of money held. English economist Arthur Cecil Pigou (1877-1959), in particular, asserted that the nominal demand for money was a constant percentage of nominal income.In the Cambridge Equation, PT is replaced by Y (the income velocity of circulation). The equation is:V = Y / Mwhere M is money stock in economy, Y income velocity of circulation and V average velocity of circulation.Monetarists argue that an increase in prices would not lead to inflation unless the government increased the money supply.
Why cant a country manufacture unlimited currency notes to become rich?
Basically, strictly printing money increases the price level by not the actual ability to produce goods, so a country doesn't become richer in real terms.Money serves as a medium of exchange and a store of value for goods. The value of currency, therefore, depends on its ability to be exchanged for goods (this is called the real value). In modern economic theory, it is generally assumed, from this fact, that all production in the economy must be exchanged with all currency. In simple model, the relationship is like thisP*Y = V*Mwhere P is the price level, Y is the GDP, V is the velocity of money (how fast it is spent) and M is the supply of money. Assuming V is constantP*Y = MImagine we increase M infinitely. If GDP (or our ability to produce things) hasn't changed, then P must increase at the ratio of M/Y to compensate. That is, we must accordingly increase the price level of the economy by an equal amount to compensate for having more money. In real life, this growth occurs and it is called inflation. Thus, while printing money will increase P*Y, or the nominal value of the economy, we're still producing as many things as before (real value has not changed) and no one is better off; we have more money, but everything simply costs more.
What is the formulae for velocity?
Below are all formulas for average velocity, which is useless if you have something that has acceleration and/or starts at a certain speed. The equation for constant acceleration is:V = V0 + atWhere V0 is the initial velocity (Which can be 0 if the initial velocity is unknown), a is the acceleration and t is the time.The equation is distance over time!The equation for velocity is:V=(Δd)/(Δt)ΔV-is the velocityΔd-is the change in displacementΔt-is the change in timenote that Δd and V are vector quantities so direction is important. Δt.is a scalor quantity so it needs no direction.e.g.:Δd=15 km[south]Δt=30 minlet south be positiveV=15 km[south]/30minV=0.5 km/min[south]if needed convert min to sec by multiplying by 60e.g.:30*60=1800 secv = d / t (or v = dd/dt & v = integral of acceleration with respect to time for physics involving calculus)where V is velocity, d is displacement (distance traveled) and t is time.vf = vi + a*t(vf)^2 = (vi)^2 + 2*a*dwhere vf is final velocity, vi is initial velocity, and a is accelerationv = p/mwhere p is object's momentum and m is object's massand much much more
What is the freezing point depression of an aqueous solution containing 25.0 grams of magnesium chloride?
You need to know the mass of the water (in kilograms) in the solution to do this problem. Without that, you cannot solve for the answer!However, if you did know that, then you could use the following equation:∆T = i * Kf * mwhere ∆T is the change in the freezing point, "i" is the number of molecules or ions formed upon addition to the solvent, Kf is the freezing point depression constant, and "m" is the molality of the solution (this is where you need the amount of water).The Kf of water for a freezing point depression is known and is equal to -1.858 K·kg/mol (or -1.858 °C molal-1)The value of "i" has to do with what you add to the water. If you added sugar, a molecular compound the value of "i" is 1.0. If you add a ionic compound like NaCl, the value of "i" is 2.0 because for every 1 molecule of NaCl, you make 2 ions: one Na+ and one Cl- in water. For MgCl2, the value of "i" is thus 3.0 (for each MgCl2 you get one Mg2+ and two Cl- ions, so a total of 3 ions).To find "m," the molality of a solution you need to know the number of moles of solute and the number of kilograms of solvent (m = moles/kg). The number of moles of solute here is found from the mass of the MgCl2 and its molar mass. However, you can't actually find the molality of the solution without knowing how many kilograms of water are in it.The molar mass of MgCl2 is:24.305 + 2*35.453 = 95.211 grams per mole.So if you have grams, you divide by the molar mass to get moles:25.0 ÷ 95.211 moles = 0.26257 moles.So to find the freezing point depression, you put this all together like this:∆T = 3.0 * -1.858 °C·kg/mol * 0.26257 mol ÷ (insert kilograms of water here)
How do you solve molality?
To solve boiling point elevation problems, you need to know the following things:-- the identity of the solute (the thing you are adding to the liquid)-- the identity of the solvent (the liquid)-- whether the solute is molecular or ionic, and if ionic, how many ions it forms-- the amount of solute (in grams or moles)-- the amount of solvent (in kilograms)-- the value of Kf of the solvent (for water, it is 0.52 K·kg/mol (or 0.52 °C molal-1)Then you use the following equation:∆T = i * Kf * mwhere ∆T is the change in the freezing point, "i" is the number of molecules or ions formed upon addition to the solvent, Kf is the freezing point depression constant, and "m" is the molality of the solution.The Kf of water for a boiling point elevation is known and is equal to 0.52 °C·kg/mol (or 0.52 °C molal-1). Notice it is positive -- for freezing point depression problems, the value of Kf is negative.The value of "i" has to do with what you add to the water. If you added sugar, a molecular compound the value of "i" is 1.0. If you add a ionic compound like NaCl, the value of "i" is 2.0 because for every 1 molecule of NaCl, you make 2 ions: one Na+ and one Cl- in water. For MgCl2, the value of "i" is thus 3.0 (for each MgCl2 you get one Mg2+ and two Cl- ions, so a total of 3 ions).To find "m," the molality of a solution you need to know the number of moles of solute and the number of kilograms of solvent (m = moles/kg). If you are given the number of grams of solute, the number of moles is found from the mass and the molar mass of the solute.grams of solute ÷ molar mass of solute = moles of soluteTo find the molality, just divide the moles of solute by the kilograms of solvent moles of solute ÷ kilograms solvent = molality Note: If you are given the volume of the solvent instead of the mass, use the density of the solvent to convert -- the density of water is 1 kilogram per liter)Liters of solvent * density of solvent = kilograms of solventNow just plug all the numbers into the equation at the top of the answer!See the Web Links and Related Questions for more information!
How could you use the spring scale to measure mass on the moon?
Metric Units:First lets consider metric units, so consider that the scale is measuring kilograms. A spring scale uses the following equation to calculate mass:k*x / g = mwhere k is the spring constant, x is the deformation of the spring (due to gravity), g is the gravity constant, and m is the mass in kilograms. The scale probably won't work because it is calibrated to use Earth's gravity constant, g = ~9.81 m/s^2. If that value is changed then you can use the scale on a different planetary body.English Units:Now to discuss the extremely confusing English units of pounds. It should be important to recognize the difference between mass pounds and force pounds in English units. Sometimes these are referred to as lb-m and lb-f (respectively) to alleviate confusion. A pound mass is the amount of mass that weighs one pound force on Earth. This unit is really only relevant on Earth, should probably never be used, and is replaced in engineering and science by the unit of Slugs. (For more on the topic of Slugs check out the articles on wikipedia, or do a google search.) A scale that calculates force pounds uses the equation:k*x = Fwhere F is the force or "weight" of your body due to gravity. By definition, to convert from Force-Pounds to Mass-Pounds, we have to multiply by 1, so on Earth the scale will tell your mass and your weight (since they are the same number, but not the same unit). Your scale will properly measure Force-pounds, or the "weight" of the object on a different planet, but it will not measure properly the mass of the object.
