The maximum size of an array in C++ is the same as the maximum number that can be represented by an int (usually 2,147,483,647 elements, or just over 2 billion). An int is defined as being dependent on a CPU's architecture, so the 2 billion number is based on 32-bit compilation. Some 64-bit processors also compile to a 32-bit int, and would be limited to just over 2 billion elements.
Available memory is also a consideration on the maximum size of an array. The larger the elements, the fewer elements you can achieve. This is unlikely to be a problem on 64-bit systems, but on 32-bit systems it could be.
Platform-dependent.
Yes you can overload the static method. But it should be avoided because memory to static methods are allocated at the time of class load.....so memory will be wasted if we don't use that methods. Whereas non-static method memory allocation depends on Object
Use sizeof( ).
No. The static keyword only specifies the way a method is declared, used and handled by the JVM and the other classes and does not modify the size it occupies in the memory.
You can have as many as you can fit in memory, which is dependent on size of each node, OS, amount of RAM, etc.
It depends how the array is declared (fixed size or variable size) and where it is declared (global scope or local scope). If the array is declared in global scope (outside a function) and is fixed size, it will be allocated in static memory. If it is variable size, the pointer is stored in static memory while the array itself is allocated on the heap. The pointer in static memory points to the start address of the array in heap memory. If the array is declared in local scope (inside a function) and is fixed size, it will be allocated on the stack in whichever thread the function was called. If it is variable size, the local pointer is stored on the stack while the array is allocated on the heap. The pointer will fall from scope when the function returns so the array must not be allowed to outlive the function in which the pointer is declared. If the array must outlive the function that allocates the array, the pointer must be declared at a higher scope in the call stack and must be passed by reference to or returned by value from the function that allocates the array. If you provide your own memory manager, however, an array may be allocated wherever the memory manager's memory pool is allocated, be it in static memory, the stack or the heap. A memory manager essentially allocates an array of bytes which you can then utilise as you see fit (the array of bytes will be allocated as per the previous description for arrays in general).
static memory management i.e we are fixed the memory location with there size & that fixed size jobs will appear
There is no preset limit on the size of an else-if ladder in C++. It depends on compiler design and available memory.
static memory management i.e we are fixed the memory location with there size & that fixed size jobs will appear
The maximum memory that can be dynamically allocated depends on the size of the heap memory. Dynamic blocks of memory can be allocated in system heap until it is not full.
The maximum size of the microSD card on the N82 is 8GB.
Yes you can overload the static method. But it should be avoided because memory to static methods are allocated at the time of class load.....so memory will be wasted if we don't use that methods. Whereas non-static method memory allocation depends on Object
it depends on the size of the memory card inserted into the DSTT. The maximum is 4 Gig.
Use sizeof( ).
That depends on the operating system and computer architecture.
The maximum size of a cache memory is theoretically equal to the amount of primary memory(RAM).Like Cache only memory architecture where the whole memory space is filled up with the cache only.
No. The static keyword only specifies the way a method is declared, used and handled by the JVM and the other classes and does not modify the size it occupies in the memory.
Having had a good look on eBay - the maximum size appears to be 32GB.