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Metal alloy that is 18 percent copper how many ounces of an alloy that is 14 percent copper must be mixed with an alloy that is 23 percent copper to form 90 ounces of alloy?
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The mass or weight w of the desired 18 % copper alloy may be calculated from the masses of the two kinds of distinct alloys specified to be mixed and their masses, M for the copper-rich alloy and m for the lower copper alloy, from the formula 0.23M + 0.14m = 0.18 (M + m). Furthermore, M + m is stated to be 90, so that M = 90 - m. Therefore
0.23(90 - m) + 0.14m = 0.18 X 90 = 16.2. Multiplying out and collecting like terms results in 20.7 - (0.23 + 0.14)m = 16.2 or 0.09m = 4.5 or m = 50 ounces. M = 90 - 50 = 40 ounces.
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A statute is made of bronze which is an alloy of about 80 percent copper and 20 percent tin Which metal is the higher concentration in this bronze statue?
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How much of an alloy that is 10% copper should be mixed with 400 ounces of an alloy that is 70% copper in order to get an alloy that is 20%
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How much of alloy that is 20 percent copper should be mixed with 200 ounces of an alloy that is 50 percent copper in order to get an alloy that is 30 percent copper?
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Is brass a pure metal?
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How much of an alloy that is 10 percent copper should be mixed with an alloy that is 80 percent copper in order to get an alloy that is 30 percent copper?
Let me reduce that to an equation for you: 10x + 80(1-x) = 30; solve for x.
A statute is made of bronze which is an alloy of about 80 percent copper and 20 percent tin Which metal is the higher concentration in this bronze statue?
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