The mass or weight w of the desired 18 % copper alloy may be calculated from the masses of the two kinds of distinct alloys specified to be mixed and their masses, M for the copper-rich alloy and m for the lower copper alloy, from the formula 0.23M + 0.14m = 0.18 (M + m). Furthermore, M + m is stated to be 90, so that M = 90 - m. Therefore
0.23(90 - m) + 0.14m = 0.18 X 90 = 16.2. Multiplying out and collecting like terms results in 20.7 - (0.23 + 0.14)m = 16.2 or 0.09m = 4.5 or m = 50 ounces. M = 90 - 50 = 40 ounces.
There is a higher concentration of copper in a bronze statue. This is because there is a higher percentage of bronze metal in the statue.
yes. It is a non ferrous metal in that it is an alloy of copper and zinc. Ferrous refers to iron, the elemental symbol for iron is Fe.
An alloy is a mixture of two or more elements where the main component is metal. Copper is a pure metal. Alloys are useful because most pure metals are too soft, brittle, or reactive for practical use.
Bronze is an alloy composed primarily of copper and tin, with the proportion of these two elements varying based on the desired characteristics of the bronze. Other elements, such as aluminum, manganese, or silicon, may also be added in smaller amounts to modify its properties.
The word used to describe a mixture that is 85% copper and 15% tin is bronze. Bronze is an alloy made by mixing copper and tin in various proportions to achieve different properties like increased durability and strength.
200 ounces.
How much of an alloy that is 10% copper should be mixed with 400 ounces of an alloy that is 70% copper in order to get an alloy that is 20%
900 ounces. Since this contains 20% copper, The copper content will be 180 ounces. The original 300 ounces contain 30% copper which is also 180 ounces. Hence in the resulting mixture of 1200 ounces (300+900), the total copper is 360 ounces (180+180). Hence the copper content of resulting mixture is 360/1200 which is 30%
Since the percentages of copper in the two components to be mixed are symmetric about the desired result, the answer is that the same amounts should be used. 600 ounces of the 30% copper.
LET X be the weigh tof the 20% alloy and then the total weight of the 30% alloy is 200 +X then 0.20X + .50 (200) = .30 (200 +X) .20X + 100 = 60 + .3X 40 = .1X 400 = X = 400 ounces
copper is NOT an alloy, it is an elemental metal
There is a higher concentration of copper in a bronze statue. This is because there is a higher percentage of bronze metal in the statue.
Let ( x ) be the amount of the 40% copper alloy needed. The equation based on the copper content is: [ 0.40x + 0.70(500) = 0.50(x + 500) ] Solving this equation, we find: [ 0.40x + 350 = 0.50x + 250 ] [ 100 = 0.10x ] [ x = 1000 ] Thus, you need to mix 1000 ounces of the 40% copper alloy with 500 ounces of the 70% copper alloy to obtain an alloy that is 50% copper.
To create an alloy with 40% copper, you would need to mix equal parts of the 20% alloy with the 70% alloy. This means you need to mix 50 ounces of the 20% alloy with 50 ounces of the 70% alloy to achieve the desired 40% copper content in the final alloy.
The alloy you are describing with 57% silver, 40% copper, and 3% tin is called "sterling silver." It is a popular metal choice for jewelry and silverware due to its durability and shine.
Alloy
Let me reduce that to an equation for you: 10x + 80(1-x) = 30; solve for x.