40 parts of 20 % plus 60 parts of 70 %
LET X be the weigh tof the 20% alloy and then the total weight of the 30% alloy is 200 +X then 0.20X + .50 (200) = .30 (200 +X) .20X + 100 = 60 + .3X 40 = .1X 400 = X = 400 ounces
Copper is typically mixed with gold to create a red hue. The higher the copper content in the alloy, the redder the gold will appear.
Brass is mainly an alloy of copper and zinc. Some alloys do have small amounts of arsenic added also.
If aluminum is mixed with copper, they can form an alloy called aluminum bronze. This alloy exhibits improved strength and corrosion resistance compared to pure aluminum or copper. The properties of the alloy can be tailored by adjusting the ratio of aluminum to copper.
Copper turns into the alloy brass by combining it with zinc. The amount of zinc added to the copper determines the properties of the brass, such as its color and strength. The mixture is heated to high temperatures to enable the zinc to bond with the copper and form a homogenous alloy.
How much of an alloy that is 10% copper should be mixed with 400 ounces of an alloy that is 70% copper in order to get an alloy that is 20%
200 ounces.
Since the percentages of copper in the two components to be mixed are symmetric about the desired result, the answer is that the same amounts should be used. 600 ounces of the 30% copper.
LET X be the weigh tof the 20% alloy and then the total weight of the 30% alloy is 200 +X then 0.20X + .50 (200) = .30 (200 +X) .20X + 100 = 60 + .3X 40 = .1X 400 = X = 400 ounces
900 ounces. Since this contains 20% copper, The copper content will be 180 ounces. The original 300 ounces contain 30% copper which is also 180 ounces. Hence in the resulting mixture of 1200 ounces (300+900), the total copper is 360 ounces (180+180). Hence the copper content of resulting mixture is 360/1200 which is 30%
Let ( x ) be the amount of the 40% copper alloy needed. The equation based on the copper content is: [ 0.40x + 0.70(500) = 0.50(x + 500) ] Solving this equation, we find: [ 0.40x + 350 = 0.50x + 250 ] [ 100 = 0.10x ] [ x = 1000 ] Thus, you need to mix 1000 ounces of the 40% copper alloy with 500 ounces of the 70% copper alloy to obtain an alloy that is 50% copper.
The mass or weight w of the desired 18 % copper alloy may be calculated from the masses of the two kinds of distinct alloys specified to be mixed and their masses, M for the copper-rich alloy and m for the lower copper alloy, from the formula 0.23M + 0.14m = 0.18 (M + m). Furthermore, M + m is stated to be 90, so that M = 90 - m. Therefore 0.23(90 - m) + 0.14m = 0.18 X 90 = 16.2. Multiplying out and collecting like terms results in 20.7 - (0.23 + 0.14)m = 16.2 or 0.09m = 4.5 or m = 50 ounces. M = 90 - 50 = 40 ounces.
Let me reduce that to an equation for you: 10x + 80(1-x) = 30; solve for x.
The industrial name for a gold-copper alloy is Rose Goldor Tumbaga.If you also add silver to the alloy you get Electrum.
Designate the weight in ounces of the first alloy, containing 40 percent copper, as w. Then, from the problem statement and the fact that percentages can be converted to decimals by dividing by 100, 0.40w + (0.80)(400) = 0.60(400 + w). Applying the usual methods of algebra, multiplying out results in: 0.40 w + 320 = 240 + 0.60w; transposing like terms with sign change and collecting results in: (0.40 - 0.60)w = 240 -320; or -0.20 w = -80, or w = 400.
Copper is typically mixed with gold to create a red hue. The higher the copper content in the alloy, the redder the gold will appear.
Brass is mainly an alloy of copper and zinc. Some alloys do have small amounts of arsenic added also.