Let ( x ) be the amount of the 40% copper alloy needed. The equation based on the copper content is:
[ 0.40x + 0.70(500) = 0.50(x + 500) ]
Solving this equation, we find:
[ 0.40x + 350 = 0.50x + 250 ] [ 100 = 0.10x ] [ x = 1000 ]
Thus, you need to mix 1000 ounces of the 40% copper alloy with 500 ounces of the 70% copper alloy to obtain an alloy that is 50% copper.
One word answer: Zinc
A ratio of 62 times 1 times 2 times 37 by 12 equals 99 mass of copper.
The Shang Dynasty mixed copper and tin to create bronze. This alloy was stronger and more durable than pure copper, allowing the Shang people to create advanced weapons, tools, and ceremonial objects.
When two alloys are mixed together, they form a new alloy that combines the properties of both original alloys. The resulting alloy may have different physical and chemical properties compared to the individual alloys. The properties of the new alloy depend on the composition and the proportions of the original alloys mixed.
they are not mixed
How much of an alloy that is 10% copper should be mixed with 400 ounces of an alloy that is 70% copper in order to get an alloy that is 20%
200 ounces.
Since the percentages of copper in the two components to be mixed are symmetric about the desired result, the answer is that the same amounts should be used. 600 ounces of the 30% copper.
LET X be the weigh tof the 20% alloy and then the total weight of the 30% alloy is 200 +X then 0.20X + .50 (200) = .30 (200 +X) .20X + 100 = 60 + .3X 40 = .1X 400 = X = 400 ounces
To create an alloy with 40% copper, you would need to mix equal parts of the 20% alloy with the 70% alloy. This means you need to mix 50 ounces of the 20% alloy with 50 ounces of the 70% alloy to achieve the desired 40% copper content in the final alloy.
900 ounces. Since this contains 20% copper, The copper content will be 180 ounces. The original 300 ounces contain 30% copper which is also 180 ounces. Hence in the resulting mixture of 1200 ounces (300+900), the total copper is 360 ounces (180+180). Hence the copper content of resulting mixture is 360/1200 which is 30%
The mass or weight w of the desired 18 % copper alloy may be calculated from the masses of the two kinds of distinct alloys specified to be mixed and their masses, M for the copper-rich alloy and m for the lower copper alloy, from the formula 0.23M + 0.14m = 0.18 (M + m). Furthermore, M + m is stated to be 90, so that M = 90 - m. Therefore 0.23(90 - m) + 0.14m = 0.18 X 90 = 16.2. Multiplying out and collecting like terms results in 20.7 - (0.23 + 0.14)m = 16.2 or 0.09m = 4.5 or m = 50 ounces. M = 90 - 50 = 40 ounces.
Let me reduce that to an equation for you: 10x + 80(1-x) = 30; solve for x.
The industrial name for a gold-copper alloy is Rose Goldor Tumbaga.If you also add silver to the alloy you get Electrum.
Designate the weight in ounces of the first alloy, containing 40 percent copper, as w. Then, from the problem statement and the fact that percentages can be converted to decimals by dividing by 100, 0.40w + (0.80)(400) = 0.60(400 + w). Applying the usual methods of algebra, multiplying out results in: 0.40 w + 320 = 240 + 0.60w; transposing like terms with sign change and collecting results in: (0.40 - 0.60)w = 240 -320; or -0.20 w = -80, or w = 400.
Copper is typically mixed with gold to create a red hue. The higher the copper content in the alloy, the redder the gold will appear.
Brass is mainly an alloy of copper and zinc. Some alloys do have small amounts of arsenic added also.