The formula you are looking for is W = I x E. Watts = Amps x Volts. W = 18 x 240 = 4320. Your dryer is rated at 4320 watts.
However, just because your 240 volt outlet is rated at 18 amps does not mean that is what your appliance will draw.
If the appliance is listed (by the manufacturer) as 1500 watts, then 1500 / 240 = 6.25, would mean that it will draw 6.25 amps at 240 volts.
Note:
Within the United States, most regular size electric dryers require a 240 volt, 30 amp power source. In addition to the electric heating element, there is the drum electric motor that must be factored in determining the wattage rating. That is the reason that it is best to use the manufacturer's nameplate rating for the answer to this question.
The basic formula is watts = amps X volts, so: 20A X 240V = 4800 watts.
The formula you are looking for is W = I x E.
(W is watts, I is current in amps, E is volts)
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5280 N
To get power OHM's law says E(volts)xI(amps)=P(watts)
240x12=2880 this is assuming 100% power factor and only works for single phase loads.
The equation that you are looking for is W = I x E. Watts = Amps x Volts.
An electric clothes dryer demands 22A from a 240V outlet at approximately 90% Power Factor. The power demand on the outlet should be about 240V x 22A x 0.9 = 4.75 kW. The active components in an electric clothes dryer are the heating element (100% PF) and the electric motor that turns the tumbler (70-80% PF). The formula you are looking for is W = I x E. (W is watts, I is current in amps, E is volts)
Yes. It draws less current.
Assume the supply as DC (Only resistance given) Voltage drop = 10X10X0.12 = 12V (approx)
375 kj
Likely one of the two electric elements is going out which creates very high resistance in the circuit and therefore draws very high current (amps) and causes the breaker to trip.
4800 watts because watts = volts x amps.
An electric clothes dryer demands 22A from a 240V outlet at approximately 90% Power Factor. The power demand on the outlet should be about 240V x 22A x 0.9 = 4.75 kW. The active components in an electric clothes dryer are the heating element (100% PF) and the electric motor that turns the tumbler (70-80% PF). The formula you are looking for is W = I x E. (W is watts, I is current in amps, E is volts)
watts = volts X amps, so: 15A X 240V = 3600 watts
1.7amp
We know that Voltage = Current x Resistance, so if E = I x R, then E = 20 x 12 = 240 volts, and the dryer must be plugged into a 240 volt outlet.
Yes. It draws less current.
The formula you are looking for is W = I x E.
By Ohm's Law Voltage = Current x Resistance R = V / I = 120 / 12 = 10 Ohms
11.5 x 240 = 2760W motor.
Power (Watts) = Current (Amps) * VoltagePower = 22Amps * 240 VoltsPower = 5,280 Watts5280
P=VI so I=P/V I= 60/230 I=0.261 A
Ohm's Law says Voltage = Current x Resistance V = 5 x 24 = 120 V.