Assume the supply as DC (Only resistance given)
Voltage drop = 10X10X0.12 = 12V (approx)
We have suppose the current flow in opposite to the direction of flow of electron.AnswerA.C. current reverses direction every half-cycle.
A 10 watt bulb is defined by the voltage supply and the resulting current. So to make the math simple, suppose you have a 10 watt incandescent bulb designed to work at 20 volts. That means it will draw 1/2 amps. Watts = Volts x Amps. The resistance of the bulb is then Volts / Amps so in this case the resistance of the bulb would be 40 ohms. So our mythical bulb has a resistance of 40 ohms with 20 volts across the bulb in our example. Now if we put two of these bulbs in series with the same 20 volts we now have a total resistance of 80 ohms supplied by 20 volts and the circuit will draw 1/4 amp. This lower current will cause the bulbs to be dimmer.
Yes indeed, a current is just a moving charge. Even if the charge is on a comb, and you are physically moving the comb around the place.
on the high power what are you not suppose to touch
Same as a hermaphrodite I suppose
The input current of transistor is approximately equal to output current .Suppose in common base configuration the emmiter current is approximately equal to collector current if neglect the very small value of bae current.Even though the input resistance is not equal to output resistance,the currents are same ,so we can reliase that the transistor transfers resistance to get same currents at both ends.
resistance is 2.5 has no meaning. You need to include units!
Current tends to travel on the surface of the wire. As you decrease the cross-sectional area of a wire the resistance increases. That is why larger wires are rated for higher currents.
depending on your load resistance what are you using . suppose you are using 100 ohm load resistance than current will flow 1.5*4=6/100=0.06Amp and if you are looking for battery current capacity than mind it you are using series connection the current will not change remain same as one battery but voltage will change as i mention above 6 volt.
Blood Vessels I suppose.
I suppose you mean "fluctuate". Collector current depends mostly on the base current, If the base current changes, the collector current will change in proportion.
Assuming galvanometer has zero or negligible internal resistance. If u connect resistor R>>RL(Load resistance) and connect it parallel to RL, it will hardly cause any change in voltage across load resistance. Suppose small current Ig goes through galvanometer. Since galvanometer have zero internal resistance, Voltage across RL = Voltage across R = IgR
Nervous about middle-east tensions, I suppose.
I suppose the current worksheet would be the one you currently are working on. It is the active worksheet.
A pump or auto suppose to be plugged so no more than 2 shells in magazine and 1 in chamber
It has never been released and it never will be i suppose.
The word 'suppose' is typically used as a preposition to an assumption. In this manner it would start a frame of thought such as in the example: "Suppose I weren't here right now, what would you be doing?"