I suppose you mean "fluctuate".
Collector current depends mostly on the base current,
If the base current changes, the collector current will change in proportion.
The percentage of doping in emitter is higher than collector region.hence large current is flow to emitter than collector.
Base voltage in a transistor. There is also Vc (Collector voltage), Ve(Emitter voltage), Ic(Collector current), Ib(Base current), Ie(Emitter current), Vcc(Supply voltage), and Hfe (Forward current gain)
we should be take two point from the the graph between collector current and emitter-collector voltage.. along the horizontal line collector current is zero and emitter-collector voltage become Vcc,and along the vertical line emitter-collector voltage is zero and collector current become Vcc/RL then by this line that drow between this two point is called load line that in this line the transistor allowed to operate....
It's called saturation because the collector voltage cannot go any lower. You've done all you can do with your base current (in Common Emitter configuration) to lower the collector voltage and support the collector current.
The collector current is a multiple of the base current due to the inherent design of the BJT. In circuit analysis, barring knowing the exact amplification, I've used 50 many times - so if you have 20 uA flowing in the base, the collector current should be ~ 1mA, and the emmiter will be ~1.02mA.
the collector current is directly proportional to the base current
The percentage of doping in emitter is higher than collector region.hence large current is flow to emitter than collector.
variation in beta dc with collector current
The percentage of doping in emitter is higher than collector region.hence large current is flow to emitter than collector.
from the name itself the common collector has its collector terminal in common with both the input and output circuits of a transistor and the base current is chosen as the input current and the output current is the emitter current
the collector voltage is lowered, because the collector is essentially a current source controlled by the base emitor current
No. As base current decreases, so does collector current.
The percentage of doping in emitter is higher than collector region.hence large current is flow to emitter than collector.
No. For BJTs, they have a natural amplification, B, of current between the base current to collector current. In rough calculations, I've often used 50. So applying 20uA of current to the base of a BJT should cause 1mA of current to flow through the collector (assuming base, collector, and emitter resistors are sized appropriately so this is not limitted). The emitter will see the base current + the collector current.
as the base current is very small compared to the emitter current,the collector current is nearly equal to the emitter current..
as the base current is very small compared to the emitter current,the collector current is nearly equal to the emitter current..
Consider that current flow "enters" at the emitter and "exits" at the collector and base. Now, IE = IB + IC. Alternately, current "enters" at the collector and the base, and "exits" at the emitter. Now, IE = IB + IC