It might be somewhere else... you should be more careful with your things...
The anterior, upper part of the right atrium.The Sinoatrial Node or SA Node is located in the right Atrium of the Heart. The SA node is responsible of the normal sinus rhythm.
A paraaortic prominent lymph node is a lymph node more noticable than the others and found near the aorta.
Any device on a LAN is called a node.
The algorithm for breadth first search is to start at the root node or at an arbitrary node within the tree. First, push this node onto a queue. Then proceed as follows 1. If the queue is empty, quit the search and return a "not found" result. 2. Pop the first node from the queue. 3. If this node contains the value you seek, quit the search and return the node. 4. Enumerate the child nodes (if any), and push them onto the queue. 5. Go to step 1.
_node* search (_node* head, _key key) { _node* node; for (node=head; node != NULL;;) { if (key == node->key) return node; else if (key < node.>key) node = node->left; else node = node->right; } return node; }
for (node=head; node!=null; node=node->next) printnode(node);
Refer to http://cslibrary.stanford.edu/110/BinaryTrees.html void mirror(struct node* node) { if (node==NULL) { return; } else { struct node* temp; // do the subtrees mirror(node->left); mirror(node->right); // swap the pointers in this node temp = node->left; node->left = node->right; node->right = temp; } }
The SA node, the natural pacemaker of the heart, is found in the right atrium of the heart.
Yes. The tail node's next node is the head node, while the head node's previous node is the tail node.
Given a list and a node to delete, use the following algorithm: // Are we deleting the head node? if (node == list.head) { // Yes -- assign its next node as the new head list.head = node.next } else // The node is not the head node { // Point to the head node prev = list.head // Traverse the list to locate the node that comes immediately before the one we want to delete while (prev.next != node) { prev = prev.next; } end while // Assign the node's next node to the previous node's next node prev.next = node.next; } end if // Before deleting the node, reset its next node node.next = null; // Now delete the node. delete node;
No. A leaf node is a node that has no child nodes. A null node is a node pointer that points to the null address (address zero). Since a leaf node has no children, its child nodes are null nodes.
An intrathoracic node is a node within the chest cavity.